javascript - 如何正确地退出一个函数？

Question

所以我的推送通知工作得很好。我遇到的一个大问题是，如果用户对自己的照片点赞/发表评论，他们将收到自己的推送通知。我不知道如何解决这个问题。例如，假设我喜欢我自己的照片，我会收到推送通知“克林特喜欢你的帖子”，这就是我，如果我正在回复对我的帖子的评论，这与评论相同。 “克林特评论了你的帖子”。

这是我通过 Atom 为通知编写的代码。

exports.observeComments = functions.database.ref('/comments/{postId}/{commentId}').onCreate((snapshot, event) => {
     var postId = event.params.postId;
     var commentId = event.params.commentId;

     return admin.database().ref('/comments/' + postId + '/' + commentId).once('value', snapshot => {
       var comment = snapshot.val();
       var commentUid = comment.uid;

       return admin.database().ref('/users/' + commentUid).once('value', snapshot => {
         var commentingUser = snapshot.val();
         var username = commentingUser.username;

         return admin.database().ref('/posts/' + postId).once('value', snapshot => {
           var post = snapshot.val();
           var postOwnerUid = post.ownerUid;

           return admin.database().ref('/users/' + postOwnerUid).once('value', snapshot => {
             var postOwner = snapshot.val();

             var payload = {
               notification: {
                 body: username + ' commented on your post '

               }
             };

             admin.messaging().sendToDevice(postOwner.fcmToken, payload)
             .then((response) => {
               // Response is a message ID string.
               console.log('Successfully sent message:', response);
               return response;
             })
             .catch((error) => {
               console.log('Error sending message:', error);
               throw new Error('Error sending message:', error);
             });
           })
         })
       })
     })
   })


exports.observeLikes = functions.database.ref('/user-likes/{uid}/{postId}').onCreate((snapshot, event) => {
     var uid = event.params.uid;
     var postId = event.params.postId;

     return admin.database().ref('/users/' + uid).once('value', snapshot => {
       var userThatLikedPost = snapshot.val();

       return admin.database().ref('/posts/' + postId).once('value', snapshot => {
         var post = snapshot.val();

         return admin.database().ref('/users/' + post.ownerUid).once('value', snapshot => {
           var postOwner = snapshot.val();

           var payload = {
             notification: {
               body: userThatLikedPost.username + ' liked your post '
             }
           };

           admin.messaging().sendToDevice(postOwner.fcmToken, payload)
           .then((response) => {
             // Response is a message ID string.
             console.log('Successfully sent message:', response);
             return response;
           })
           .catch((error) => {
             console.log('Error sending message:', error);
             throw new Error('Error sending message:', error);
           });
             });
         })
       })
     })

Answer 1

如果我理解正确，你只需要添加中断条件。只需在

之后添加

var postOwnerUid = post.ownerUid;

这一行:

if(commentUid === postOwnerUid)
  return Promise.resolve();

及之后

var post = snapshot.val();

这一行:

if(uid === post.ownerUid)
  return Promise.resolve();