Python:如何捕获异常并继续？

Question

Why do you have a list of both numbers and some other kind of object? It seems like you're trying to compensate for a design flaw.

事实上，我希望它以这种方式工作，因为我想保留已经在 J​​sonedData() 中编码的数据，然后我希望 json 模块给我一些方法来插入“原始”项目数据而不是默认值，以便编码的 JsonedData 可以重用。

这是代码，谢谢

import json
import io
class JsonedData():
    def __init__(self, data):
        self.data = data
def main():
    try:
        for chunk in json.JSONEncoder().iterencode([1,2,3,JsonedData(u'4'),5]):
            print chunk
    except TypeError: pass# except come method to make the print continue
    # so that printed data is something like:
    # [1
    # ,2
    # ,3
    # , 
    # ,5]

Answer 1

将 try/except 放在 json.JSONEncoder().encode(item) 的循环中:

print "[",
lst = [1, 2, 3, JsonedData(u'4'), 5]
for i, item in enumerate(lst):
    try:
        chunk = json.JSONEncoder().encode(item)
    except TypeError: 
        pass
    else:
        print chunk
    finally:
        # dont print the ',' if this is the last item in the lst
        if i + 1 != len(lst):
            print ","
print "]"