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php - 使用具有动态生成的字段的表单测试 Controller

转载 作者:行者123 更新时间:2023-11-28 20:50:48 26 4
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我有一个具有动态字段的表单:

<?php

namespace AppBundle\Form;

//uses ...
class AnnonceType extends AbstractType
{

public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('titre')
->add('description')
->add('groupeCompetence', EntityType::class, [
'class' => 'AppBundle\Entity\GroupeCompetences',
'choice_label' => 'nom',
'placeholder' => 'Sélectionnez votre type de service',
])
->add('prix')
->add('serviceADistance')
->add('ajouter', SubmitType::class);


$formModifier = function (FormInterface $form, GroupeCompetences $groupeCompetences=null){
$competences = null === $groupeCompetences ? array() : $groupeCompetences->getCompetences();

$form->add('competence', EntityType::class, array(
'class' => 'AppBundle\Entity\Competence',
'choice_label' => 'nom',
'placeholder' => 'Choisir une compétence',
'choices' => $competences,
));
};

$builder->addEventListener(
FormEvents::PRE_SET_DATA,
function (FormEvent $event) use ($formModifier) {

// this would be your entity, i.e. CompetenceChoisie
$data = $event->getData();

//var_dump($data);
//die();

$formModifier($event->getForm(), $data->getGroupeCompetence());
}
);

$builder->get('groupeCompetence')->addEventListener(
FormEvents::POST_SUBMIT,
function (FormEvent $event) use ($formModifier) {

$groupeCompetences = $event->getForm()->getData();

$formModifier($event->getForm()->getParent(), $groupeCompetences);

}
);

}
}

我在 ajax 中有这段代码:

<script>
var $groupeCompetence = $('#requete_prestataire_groupeCompetence');
// When sport gets selected ...
$groupeCompetence.change(function() {
// ... retrieve the corresponding form.
var $form = $(this).closest('form');
// Simulate form data, but only include the selected sport value.
var data = {};
data[$groupeCompetence.attr('name')] = $groupeCompetence.val();
// Submit data via AJAX to the form's action path.
$.ajax({
url : $form.attr('action'),
type: $form.attr('method'),
data : data,
success: function(html) {
// Replace current position field ...
$('#requete_prestataire_competence').replaceWith(
// ... with the returned one from the AJAX response.
$(html).find('#requete_prestataire_competence')
);
// Position field now displays the appropriate positions.
}
});
});
</script>

事实上,能力是根据 GroupeCompetence 动态生成的。

我想在 PHPUnit 中测试它。

我试过这个:

public function testIndexRechercheUtilisateurNonConnecte()
{
$crawler = $this->client->request('GET', '/');

$form = $crawler->selectButton('requete_prestataire_Rechercher')->form();
$form['requete_prestataire[groupeCompetence]'] = 2;
$form['requete_prestataire[competence]'] = "";

$crawler = $this->client->submit($form);
$this->assertTrue($this->client->getResponse()->isRedirect());
$client->followRedirect();

/*$this->assertEquals(3, $crawler->filter('a [class = "btn-sm btn-primary"]')->count());*/


}

问题是:$form['requete_prestataire[competence]'] 如我所说是动态生成的。

我希望能够在测试中做ajax请求,然后测试输出。

我该如何继续?

提前致谢

最佳答案

我找到了解决方案:

您必须禁用验证,并在生成表单时发送它:

$crawler = $this->client->request('GET', '/');

$form = $crawler->selectButton('requete_prestataire_Rechercher')->form();
$form['requete_prestataire[groupeCompetence]'] = 2;
$form['requete_prestataire[competence]']->disableValidation()->select(50);

$crawler = $this->client->submit($form);

关于php - 使用具有动态生成的字段的表单测试 Controller ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47997463/

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