javascript - 浅复制问题

Question

我只是尝试了一些简单的 JavaScript

name = 'velu' 
fname = name
name = 'valu'
console.log(fname) // would still print as velu...

如何处理生成的对象原型(prototype)发生更改并且生成的对象仍然具有旧对象的副本的情况..

情况是这样的...

function Cat(name){  
this.name = name  
}
var garfield = new Cat('Garfield')
Cat.prototype.greet = function(){
console.log('Meow, I am ' + this.name)
}
function Animal(){}
Cat.prototype = new Animal
Cat.prototype.constructor = Cat 
Animal.prototype.breed = function(){
console.log('Making a new animal!')
return new this.constructor()
}
 var kitty = garfield.breed() // this will not work as it garfield still is pointing to the old prototype object of Cat ...

谢谢

Answer 1

您必须创建一个对象，该对象通过引用传递:

var name = { Value: 'velu' };
var fname = name;
name.Value = 'valu';
console.log(fname.Value);