python - 根据值从列表中删除 namedtuple

Question

考虑以下扩展 list 并附加 orderedtuple 的类:

from collections import namedtuple

Order = namedtuple('Order', ['id', 'value'])


class Orders(list):
    def __init__(self, *args):
        super(Orders, self).__init__()
        self.extend(args)

    def add(self, id, value):
        self.append(Order(id, value))

...添加一些元素...

order = Orders()

order.add(1, 'alpha')
order.add(2, 'beta')
order.add(3, 'lambda')
order.add(4, 'omega')

...我们还剩下...

print order
[Order(id=1, value='alpha'), Order(id=2, value='beta'), Order(id=3, value='lambda'), Order(id=4, value='omega')]

假设我想通过它的 id 删除任意元素。例如:

order.remove(id=2) # ideal function call to remove by `id`
print order
[Order(id=1, value='alpha'), Order(id=3, value='lambda'), Order(id=4, value='omega')]

是否有一种相当简单的方法来实现这一点？

Answer 1

[namedtuple for namedtuple in list if namedtuple.id != 'id']