javascript - Google Places API 在 Firefox 中无法运行

Question

我完全被困住了。我使用 Google Places API 和 Google Maps Javascript API v3 来显示商业 map 及其地址、电话号码等...我在Webkit上开发了网站...然后我发现它在Firefox中不起作用...这是我的代码:

function initialize() {
var e = document.getElementById('place_reference')
if (e) {
    var place_reference = document.getElementById('place_reference').innerText;
}
var request = {
  reference: place_reference
};
service = new google.maps.places.PlacesService(document.getElementById('map_canvas'));
service.getDetails(request, callback);

function callback(place, status) {
  console.log(status);
  if (status == google.maps.places.PlacesServiceStatus.OK) {
    document.getElementById('loading').style.display = 'none';
    if (document.getElementById('place_address').innerText == '') {
        document.getElementById('place_address').innerText = place.formatted_address;
    }
    if (document.getElementById('place_phone').innerText == '') {
        document.getElementById('place_phone').innerText = place.international_phone_number;
    }
    if (document.getElementById('place_website').innerHTML == '') {
        document.getElementById('place_website').innerHTML = '<a href="' + place.website + '"target="_blank">' + place.website + '</a>';
    }  
    var place = place.geometry.location;
    var marker;
    var map;
    var mapOptions = {
      zoom: 16,
      mapTypeId: google.maps.MapTypeId.ROADMAP,
      disableDefaultUI: true,
      scrollwheel: false,
      center: place
    };
    map = new google.maps.Map(document.getElementById('map_canvas'),
            mapOptions);
    marker = new google.maps.Marker({
      map: map,
      draggable: false,
      animation: google.maps.Animation.DROP,
      position: place
    });
  }
}
}

在 Firefox 上，状态返回 INVALID_REQUEST，而在其他浏览器上，状态返回 OK

我真的需要帮助来解决这个问题。您可以通过以下地址查看网站:http://social-e.laclinique.biz/en/blog/shops/noel-eternel

Answer 1

问题在这里:

 var place_reference = document.getElementById('place_reference').innerText;

FF 不支持innerText，请使用例如:

 var place_reference = document.getElementById('place_reference').firstChild.nodeValue

(或)

 var place_reference = document.getElementById('place_reference').innerHTML;