python - 引用所需字典(Python)索引的更简单方法？

Question

问题感觉措辞不当，如果您同意并知道如何更好地措辞，请随时进行调整。

我有以下代码:

def owned_calendars(cal_items):
    """Returns only the calendars in which the user is marked as "owner"

    """
    owner_cals = []
    for entry in cal_items:
        if entry['accessRole'] == "owner":
            owner_cals.append(cal_items[cal_items.index(entry)])

    return owner_cals

cal_items 是字典的列表

在我写的行中 owner_cals.append(cal_items[cal_items.index(entry)]) 我试图附加具有属性 accessRole = owner.

这条线看起来又长又笨重，我想知道是否有更简单/更直观的方法来做到这一点？

Answer 1

试试这个。您可以使用 list comprehension 在一行中完成此操作.

owner_cals = [x for x in cal_items if x["access_role"]=="owner"]

您还可以使用 enumerate方法。

owner_cals = [j for i,j in enumerate(cal_items) if j["access_role"]=="owner"]

另外，请记住 .index() 返回找到项目的最低索引。

["foo", "bar", "baz", "bar"].index("bar") 将始终返回 1。