javascript - 从构造函数中获取对象的所有 JavaScript 函数，而不是使用 "this"分配的函数？

Question

我需要获取构造函数内的所有函数名称，排除那些使用 this 分配的函数:

var MyObject = function (arg1, arg2) {
    this.arg1 = arg1;
    this.arg2 = arg2;

    // Get all functions, i.e. 'foo', excluding 'arg1' and 'arg2'
};

MyObject.prototype.foo = function() {}

我使用过Underscore.js，但没有运气。假设实际参数都是函数:

var MyObject = function (arg1, arg2) {
    this.arg1 = arg1;
    this.arg2 = arg2;

    // Array of object function names, that is 'foo', 'arg1' and 'arg2'
    var functions = _.functions(this);

     // Loop over function names
    _.each(functions, function (name) {}, this) {
        // Function arguments contain this.name? Strict check ===
        if(_.contains(arguments, this.name) {
            functions = _.without(functions, name); // Remove this function
        }
    }
};

MyObject.prototype.foo = function() {}

Answer 1

您要求原型(prototype)定义的所有函数:

_.functions(MyObject.prototype);