python - 由字母组成的字母

Question

我是 python(3.4 版)的新手，我想知道如何编写与此类似的代码:

#block letters 
B1 = ("BBBB  ")
B2 = ("B   B ")
B3 = ("B   B ")
B4 = ("BBBB  ")
B5 = ("B   B ")
B6 = ("B   B ")
B7 = ("BBBB  ")
B = [B1, B2, B3, B4, B5, B6, B7]

E1 = ("EEEEE ")
E2 = ("E     ")
E3 = ("E     ")
E4 = ("EEEEE ")
E5 = ("E     ")
E6 = ("E     ")
E7 = ("EEEEE ")
E = [E1, E2, E3, E4, E5, E6, E7]

N1 = ("N    N")
N2 = ("NN   N")
N3 = ("N N  N")
N4 = ("N N  N")
N5 = ("N  N N")
N6 = ("N   NN")
N7 = ("N    N")
N = [N1, N2, N3, N4, N5, N6, N7]
for i in range(7):
    print(B[i], E[i], N[i])

我当前代码的输出如下所示:

BBBB   EEEEE  N    N
B   B  E      NN   N
B   B  E      N N  N
BBBB   EEEEE  N N  N
B   B  E      N  N N
B   B  E      N   NN
BBBB   EEEEE  N    N

但我想知道如何制作一个可以接受用户输入并以上述样式打印的。我已经尝试了几个小时但无法提出解决方案，很高兴看到其他人如何做/已经做到了。我认为当屏幕上放不下字母时会变得更加困难，所以我只想打印 10 个字母。谢谢

Answer 1

Assumption: you have all the letters constructed and that all letters have the same number of rows.

在这种情况下，您可以构建字典，例如:

ascii_art = { 'B': B, 'E': E, 'N': N }

当然在现实生活中，您会构建一个包含所有字母、可能还有空格、数字等的字典。

现在您可以将字符串作为输入:

text = input('Enter text? ')

接下来我们将字符串映射到一个可迭代的字母上:

chars = map(ascii_art.get,text)

最后我们将它们放入一个 zip 中并打印出来:

for d in zip(*chars):
    print(*d)

或者把它们放在一起:

ascii_art = { 'B': B, 'E': E, 'N': N }
text = input('Enter text? ')
chars = map(ascii_art.get,text)
for d in zip(*chars):
    print(*d)

如果您想将输出限制为每行 10 个字符，您可以将代码更改为:

ascii_art = { 'B': B, 'E': E, 'N': N }
text = input('Enter text? ')
for i in range(0,len(text),10):
    chars = map(ascii_art.get,text[i:i+10])
    for d in zip(*chars):
        print(*d)

这导致:

Enter text? BEBEBEBBEBEENNNENNNN
BBBB   EEEEE  BBBB   EEEEE  BBBB   EEEEE  BBBB   BBBB   EEEEE  BBBB  
B   B  E      B   B  E      B   B  E      B   B  B   B  E      B   B 
B   B  E      B   B  E      B   B  E      B   B  B   B  E      B   B 
BBBB   EEEEE  BBBB   EEEEE  BBBB   EEEEE  BBBB   BBBB   EEEEE  BBBB  
B   B  E      B   B  E      B   B  E      B   B  B   B  E      B   B 
B   B  E      B   B  E      B   B  E      B   B  B   B  E      B   B 
BBBB   EEEEE  BBBB   EEEEE  BBBB   EEEEE  BBBB   BBBB   EEEEE  BBBB  
EEEEE  EEEEE  N    N N    N N    N EEEEE  N    N N    N N    N N    N
E      E      NN   N NN   N NN   N E      NN   N NN   N NN   N NN   N
E      E      N N  N N N  N N N  N E      N N  N N N  N N N  N N N  N
EEEEE  EEEEE  N N  N N N  N N N  N EEEEE  N N  N N N  N N N  N N N  N
E      E      N  N N N  N N N  N N E      N  N N N  N N N  N N N  N N
E      E      N   NN N   NN N   NN E      N   NN N   NN N   NN N   NN
EEEEE  EEEEE  N    N N    N N    N EEEEE  N    N N    N N    N N    N

我们可以通过添加一个额外的语句来每行添加一个空行:

ascii_art = { 'B': B, 'E': E, 'N': N }
text = input('Enter text? ')
for i in range(0,len(text),10):
    chars = map(ascii_art.get,text[i:i+10])
    for d in zip(*chars):
        print(*d)
    <b>print()</b>

这会产生:

Enter text? BBBEEEEEEENNNNN
BBBB   BBBB   BBBB   EEEEE  EEEEE  EEEEE  EEEEE  EEEEE  EEEEE  EEEEE 
B   B  B   B  B   B  E      E      E      E      E      E      E     
B   B  B   B  B   B  E      E      E      E      E      E      E     
BBBB   BBBB   BBBB   EEEEE  EEEEE  EEEEE  EEEEE  EEEEE  EEEEE  EEEEE 
B   B  B   B  B   B  E      E      E      E      E      E      E     
B   B  B   B  B   B  E      E      E      E      E      E      E     
BBBB   BBBB   BBBB   EEEEE  EEEEE  EEEEE  EEEEE  EEEEE  EEEEE  EEEEE 

N    N N    N N    N N    N N    N
NN   N NN   N NN   N NN   N NN   N
N N  N N N  N N N  N N N  N N N  N
N N  N N N  N N N  N N N  N N N  N
N  N N N  N N N  N N N  N N N  N N
N   NN N   NN N   NN N   NN N   NN
N    N N    N N    N N    N N    N