ios - 将对象添加到另一个 NSDictionary 中的 NSMutableDictionary 中的 NSMutableArray

Question

所以我在字典中有一个包含数组的字典。我正在尝试添加到第二个字典中的数组。

 [mealInfo setObject:[[NSMutableDictionary alloc]init] forKey:@"breakfast"];
 [[mealInfo objectForKey:@"breakfast"] setObject:[[NSMutableArray alloc] init] forKey:@"name"];
    [[mealInfo objectForKey:@"breakfast"] setObject:[[NSMutableArray alloc] init] forKey:@"detail"];
    [[mealInfo objectForKey:@"breakfast"] setObject:[[NSMutableArray alloc] init] forKey:@"ndb"];
    [[mealInfo objectForKey:@"breakfast"] setObject:[[NSMutableArray alloc] init] forKey:@"id"];
    [[mealInfo objectForKey:@"breakfast"] setObject:[[NSMutableArray alloc] init] forKey:@"alias"];

创建似乎工作只是向数组添加多个元素是我最终遇到 SIGABRT 错误的地方

我这样加

[[[initMealInfo->mealInfo objectForKey:@"breakfast"] objectForKey:@"name"] addObject:[food_prop objectForKey:@"description"]];

我知道我做错了什么，想知道有什么帮助将不胜感激。

Answer 1

首先，您使用的是 ARC 吗？否则你会遇到很多麻烦。

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您应该阅读最少知识原则和 Law Of Demeter

正在使这样的结构更直观:

    NSMutableDictionary *mealInfo = [[NSMutableDictionary alloc] init];

    NSMutableDictionary *breakfast = [[NSMutableDictionary alloc] init];
    [breakfast setObject:[[NSMutableArray alloc] init] forKey:@"name"];
    [breakfast setObject:[[NSMutableArray alloc] init] forKey:@"detail"];
    [breakfast setObject:[[NSMutableArray alloc] init] forKey:@"ndb"];
    [breakfast setObject:[[NSMutableArray alloc] init] forKey:@"id"];
    [breakfast setObject:[[NSMutableArray alloc] init] forKey:@"alias"];

    [mealInfo setObject:breakfast forKey:@"breakfast"];

然后当您尝试输入信息并将其包装在函数中时，尝试将其分解一下

-(void) addMealName:(NSString*) name forMeal:(NSString*) meal 
{
    NSMutableDictionary *meals = [mealInfo objectForKey:meal];
    NSMutableArray *mealNames = [breakfast objectForKey:@"name"];
    [mealNames addObject:name];
    [meals setObject:breakfastNames forKey:@"name"];
    [mealInfo breakfast forKey:meal];
}

然后打电话

NSString *newMealName = [food_prop objectForKey:@"description"];
[initMealInfo addMealName:newMealName forMeal:@"breakfast"];