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javascript - Greensock 嵌套时间线未按预期运行

转载 作者:行者123 更新时间:2023-11-28 20:33:42 24 4
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我有以下代码:

var mainTimeLine = new TimelineLite({paused:true});

var whiteGlow = "0px 0px 30px rgba(255,255,255,0.5), 0px 0px 30px rgba(255,255,255,0.5), 0px 0px 30px rgba(255,255,255,0.5), 0px 0px 30px rgba(255,255,255,0.5)";

var slide1 = document.getElementById("slide1"); //or use jQuery's $("#photo")
var circle11 = document.getElementById("circle1-1"); //or use jQuery's $("#photo")
var circle12 = document.getElementById("circle1-2"); //or use jQuery's $("#photo")
var backgroundLines1 = document.getElementById("backgroundLines1"); //or use jQuery's $("#photo")
//TweenMax.to(backgroundLines1, 2, {right:"100px", repeat:-1, ease:Linear.easeNone});

var text11 = document.getElementById("text1-1"); //or use jQuery's $("#photo")
var text12 = document.getElementById("text1-2"); //or use jQuery's $("#photo")
var text13 = document.getElementById("text1-3"); //or use jQuery's $("#photo")
var man1 = document.getElementById("man1"); //or use jQuery's $("#photo")
var idgLogo = document.getElementById("idg-logo"); //or use jQuery's $("#photo")

var slide2 = document.getElementById("slide2"); //or use jQuery's $("#photo")

var slide3 = document.getElementById("slide3"); //or use jQuery's $("#photo")

//slide1.style.display = 'block';

//slide1.style.display = 'block';
var slide11Timeline = new TimelineLite();
var slide12Timeline = new TimelineLite();

var slide1Timeline = new TimelineLite({paused:false});


slide11Timeline.add([
TweenLite.to(slide1, 0, {left:"0"}),
TweenMax.to(circle11, 60, {rotation:360, repeat:-1, ease:Linear.easeNone}),
TweenMax.to(circle12, 60, {rotation:-360, repeat:-1, ease:Linear.easeNone}),
TweenLite.from(circle11, 10, {opacity:"0.0"}),
TweenLite.from(circle12, 10, {opacity:"0.0"}),
TweenLite.from(text11, 1, {opacity:"0.0"})
]);

slide12Timeline
.from(text11, 1, {top:"-40px", ease:Expo.easeOut,delay:2})
.to(text11, 2, {
textShadow:whiteGlow
//color:"#91ff00"
})
.from(text12, 1, {opacity:"0.0"})
.from(text13, 1, {opacity:"0.0"})
.from([idgLogo, man1], 1, {opacity:"0.0"})
.to(slide1, 2, {left:"-10000", delay:2});


slide1Timeline.add([slide11Timeline,slide12Timeline]);


var slide21Timeline = new TimelineLite({paused:false});
slide21Timeline.to(slide2, 1, {left:"0"});

mainTimeLine.add(slide1Timeline);
mainTimeLine.add(slide21Timeline);

mainTimeLine.play();

目前slide1Timeline 播放,但slide21Timeline 不播放。我试图让他们一个接一个地玩...我尝试了各种方法但失败了...有人可以告诉我我做错了什么吗?

最佳答案

我相信问题是你在slide11Timeline中有一些无限重复的补间,所以它的totalDuration()基本上是无穷大。您使用 add() 将它们放入 mainTimeLine 中,但请记住,默认情况下,add() 将对子项进行排序,使用时间线的末尾作为插入点。

由于第一个嵌套时间线的持续时间非常长,因此您永远看不到后续的 slip21Timeline 动画,因为它在 mainTimeLine 上的位置在将来WAAAAY关闭。

但是不用担心 - 您可以完全控制插入点的位置 - 只需使用 add() 的第二个参数即可。以下是一些选项:

//to make them both start at 0 (run concurrently):    
mainTimeLine.add(slide1Timeline, 0);
mainTimeLine.add(slide21Timeline, 0);

//or to make slide21Timeline run at the 60-second spot of mainTimeLine:
mainTimeLine.add(slide21Timeline, 60);

另请注意,如果您想要

关于javascript - Greensock 嵌套时间线未按预期运行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15851136/

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