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javascript - 调用其他 php 页面的脚本不起作用

转载 作者:行者123 更新时间:2023-11-28 20:31:11 24 4
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需要帮助,按钮不起作用,我的主页上的报告生成器按钮没有调用report.php页面,在Chrome中,我检查了开发人员工具下的网络选项卡,但没有得到任何事件/响应当我单击报告生成器按钮时,下面是我的主 php 页面:

<script type="text/javascript">

$(document).ready(function(){
$("#RetrieveList").on('click',function() {
var xid = $('#XiD').val();
var date = $('#Date').val();
$.post('retrieve_test.php',{xid:xid, date:date}, function(data){
$("#results").html(data);
});
return false;
});

$("#DeletefromDB").click(function() {
if (confirm("Are you sure you want to delete?"))
var id = $('input[name=checkbox]:checked').map(function()
{
return $(this).val();
}).get();
$.post('delete_test.php',{id:id}, function(data){
$("#result").html(data);
});

return false;
});
});

$("#Report").on('click',function() {
var date = $('#Date').val();
$.post('report.php',{date:date}, function(data){
$("#results").html(data);
});
return false;
});

</script>

<form id="form2" name="form2" method="post" action="">

<table width="741" border="0" align="center">
<tr>
<th colspan="9" align="center" style="font-size:14px" scope="col">Xid, Name:<span>
<select name="XiD" id="XiD">

<option value="AAA">AAA</option>
<option value="BBB">BBB</option>
<option value="" selected="selected">Please Select...</option>
</select>
</span><span style="font-size:14px">
<label for="date">Date:</label>
<input type="text" name="Date" id="Date" size="8"/>
</span></th>
</tr>
<tr>
<th colspan="9" scope="col">&nbsp;</th>
</tr>
<tr>
<th colspan="9" scope="col">
<div align="center">
<input name="action" type="button" id="RetrieveList" value="Retrieve List" />
<input name="action" type="button" id="DeletefromDB" value="Delete from DB" />
<input name="Clear" type="reset" id="Clear" value="Clear" onClick="window.location.reload()" />
<input name="action" type="button" id="Report" value="Report Generator" />
</div>
<label for="Clear"></label>
<div align="center"></div></th>
</tr>

</table>
</form>
<div id="results">
</div>

这是我的report.php页面代码:

<?php
require 'include/DB_Open.php';

$date = $_POST['date'];

$sql="SELECT trouble_type_priority, category_1, category_2, status, COUNT (*) AS Total
FROM tbl_main
WHERE resolved_date = '$date'
GROUP BY trouble_type_priority, category_1, category_2, status";

$myData = mysql_query($sql)or die(mysql_error());

echo "<table width='auto' cellpadding='1px' cellspacing='0px' border=1 align='center'>
<tr>
<th colspan='3' align='center'>Ticket Bucket</th>
<th colspan='3' align='center'>Status</th>
</tr>
<tr>
<th width='auto' align='center'>Severity</th>
<th width='auto' align='center'>Category 2</th>
<th width='auto' align='center'>Category 3</th>
<th width='auto' align='center'>Resolved</th>
<th width='auto' align='center'>Re-assigned</th>
<th width='auto' align='center'>Grand Total</th>
</tr>";

while($info = mysql_fetch_array($myData))
{
echo"<tr>";

echo "<td align='center'>" . $info['trouble_type_priority'] . "</td>";
echo "<td align='center'>" . $info['category_1'] . "</td>";
echo "<td align='center'>" . $info['category_2'] . "</td>";
echo "<td align='center'>" . $info['status'] . "</td>";
echo "</tr>";
}
echo "</table>";


include 'include/DB_Close.php';
?>

最佳答案

看起来用于设置“报告”按钮的 onclick 事件的代码位于 $(document).ready(...) 函数之外。现在,您的 JavaScript 将在页面的其余部分准备好之前执行,此时将没有报告按钮来添加事件。

我想,这可能就是问题所在。尝试将 $("#Report").on('click', ...) 移动到 $(document).ready(...) 回调函数中.

关于javascript - 调用其他 php 页面的脚本不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16339499/

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