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python : smtplib sendmail function

转载 作者:行者123 更新时间:2023-11-28 20:26:41 26 4
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我有一个激活邮件发送脚本如下。

#!/usr/bin/python

__author__ = 'Amyth Arora (***@gmail.com)'

import smtplib
import string
import sys
import random

from email.MIMEText import MIMEText


def generate_activation_key(size=64, chars=string.ascii_lowercase + string.digits):
return ''.join(random.choice(chars) for x in range(size))


def generate_activation_url(key):
return 'http://www.example.com/users/activate/' + key

def Activate(name, to_addr):
sender, reciever = 'mymail@gmail.com', to_addr
act_url = generate_activation_url(generate_activation_key())
main_mssg = """
Dear %s,

Thakyou for creating an account with Example.com. You are now just one click away from using your example account. Please click the following link to verify this email address and activate your account.

Please Note, You must complete this step to become a registered member of example. you will only need to visit this url once in order to activate your account.

============================
Activation Link Below:
============================

%s


if you are facing problems activating your account please contact our support team at
support@example.com

Best Regards,

Example Team
""" % (name, act_url)


message = MIMEText(main_mssg)
message['From'] = 'Example <' + sender + '>'
message['To'] = reciever
message['MIME-Version'] = '1.0'
message['Content-type'] = 'text/HTML'
message['Subject'] = 'Activate Your Example Account'
try:
smtpObj = smtplib.SMTP('smtp.gmail.com', 587)
smtpObj.set_debuglevel(1) # Swith On/Off Debug Mode
smtpObj.ehlo()
smtpObj.starttls()
smtpObj.ehlo()
smtpObj.login('mymail@gmail.com', 'mypass')
smtpObj.sendmail(sender, reciever, message.as_string())
smtpObj.close()
return act_url
except:
return None

def main(argv):
if len(argv) != 2:
sys.exit(1)
Activate(argv[0], argv[1])


if __name__ == '__main__':
main(sys.argv[1:])

脚本工作正常,因为我已经通过这样的命令行尝试过它:

./scriptname 'Reciepent Name' 'reciepent@gmail.com'

但是我想像这样从我的一个应用程序处理程序中调用激活脚本。

import activation

act_key = activation.Activate('Reciepent Name', 'reciepent@gmail.com')

但是当我这样做时,脚本返回 None。谁能弄清楚如何解决这个问题?

最佳答案

App Engine 不允许用户使用 smtplib 库发送电子邮件。相反,您需要使用提供的 api。文档可在此处找到:https://developers.google.com/appengine/docs/python/mail

关于 python : smtplib sendmail function,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10904418/

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