python - 返回给定字符数下的句子的函数

Question

让我们假设我有以下段落:

"This is the first sentence. This is the second sentence? This is the third
 sentence!"

我需要创建一个函数，它只返回给定字符数下的句子数。如果小于一个句子，则返回第一个句子的所有字符。

例如:

>>> reduce_paragraph(100)
"This is the first sentence. This is the second sentence? This is the third
 sentence!"

>>> reduce_paragraph(80)
"This is the first sentence. This is the second sentence?"

>>> reduce_paragraph(50)
"This is the first sentence."

>>> reduce_paragraph(5)
"This "

我从这样的事情开始，但我似乎无法弄清楚如何完成它:

endsentence = ".?!"
sentences = itertools.groupby(text, lambda x: any(x.endswith(punct) for punct in endsentence))
for number,(truth, sentence) in enumerate(sentences):
    if truth:
        first_sentence = previous+''.join(sentence).replace('\n',' ')
    previous = ''.join(sentence)

Answer 1

由于英语的句法结构，处理句子非常困难。正如有人已经指出的那样，即使是最好的正则表达式，缩写等问题也会引起无休止的头痛。

您应该考虑 Natural Laungauge Toolkit .特别是 punkt模块。它是一个句子分词器，它将为您完成繁重的工作。