python - 我究竟做错了什么？随机数猜谜游戏

Question

首先，非常感谢您提供的任何答案。

无论如何，我是 Python 的初学者，一般来说是编程的初学者。我尝试创建自己的随机数猜测游戏，计算机会在 1-15 之间选择一个随机数，yada yada。

我的问题是，当我试图告诉用户他们的猜测是太低还是太高时，程序要么终止而不通知用户他们是否正确。或者它只是不断循环。

Too Low, please guess again: 14

Correct! You've guessed my number!

Too Low, please guess again: 12

Too Low, please guess again: 1

Too Low, please guess again:

这是我为这个程序编写的全部代码:

import random
from time import sleep

number = random.randint(1,15)
play = input("Hello! Would you like to play (Y/N) ")

if play in('y', 'Y'):
    sleep(.75)

    print("I've chosen a number between 1 and 15.") 
    sleep(.5)

    guess = int(input("What is my number? "))

    while guess >= number:
        guess = int(input("Too High, please guess again: "))
        if guess == number:
            print("Correct! You've guessed my number!")

    while guess <= number:
        guess = int(input("Too Low, please guess again: "))
    
        if guess == number:
            print("Correct! You've guessed my number!")
        
else:
    exit

再次感谢您的回答!

Answer 1

你的循环逻辑有点扭曲。

while guess >= number:
    guess = int(input("Too High, please guess again: "))
    if guess == number:
        print("Correct! You've guessed my number!")

while guess <= number:
    guess = int(input("Too Low, please guess again: "))

    if guess == number:
        print("Correct! You've guessed my number!")

1. 你在猜测太高时循环。低猜测会打断这一点。
2. 你在猜测太低时循环。高猜测会打断这一点。

因此，如果我们先进行低猜测，然后进行高猜测，但我们仍然不正确，我们就逃脱了 while配对，不能重试。

相反，试试这个单一的循环结构:

while guess != number:

在里面，if对于 <= , == , 和 >= .干杯!