python - 如何将单引号括在 python 字典周围以使其成为 JSON？

Question

我正在尝试从 Python 解析 JSON。如果我在 json 字符串周围使用单引号，我能够正确解析 JSON，但如果我删除该单引号，那么它对我不起作用 -

#!/usr/bin/python

import json
# getting JSON string from a method which gives me like this
# so I need to wrap around this dict with single quote to deserialize the JSON
jsonStr = {"hello":"world"} 

j = json.loads(`jsonStr`) #this doesnt work either?
shell_script = j['hello']
print shell_script

所以我的问题是如何将该 JSON 字符串用单引号括起来，以便我能够正确反序列化它？

我得到的错误 -

$ python jsontest.py
Traceback (most recent call last):
  File "jsontest.py", line 7, in <module>
    j = json.loads('jsonStr')
  File "/usr/lib/python2.7/json/__init__.py", line 326, in loads
    return _default_decoder.decode(s)
  File "/usr/lib/python2.7/json/decoder.py", line 366, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "/usr/lib/python2.7/json/decoder.py", line 384, in raw_decode
    raise ValueError("No JSON object could be decoded")
ValueError: No JSON object could be decoded

Answer 1

我认为您在 dumps() 和 loads() 之间混淆了两个不同的概念

jsonStr = {"hello":"world"} 

j = json.loads(json.dumps(jsonStr)) #this should work
shell_script = j['hello']
print shell_script

但是，是的，它是多余的，因为 jsonStr 已经是一个对象。如果您想尝试 loads()，您需要一个有效的 json 字符串作为输入，如下所示:

jsonStr = '{"hello":"world"}'

j = json.loads(jsonStr) #this should work
shell_script = j['hello']
print shell_script