python - TypeError:不支持的操作数类型 |: 'int' 和 'str'

Question

我试图解决一些关于我的错误的已经存在的问题，但没有一个能解决问题。这是我尝试运行的代码:

from random import *

location1 = randint(0,7)
location2 = location1 + 1
location3 = location2 + 1
guess = None
hits = 0
guesses = 0
isSunk = False

while (isSunk == False):
   guess = raw_input("Ready, aim, fire! (enter a number from 0-6): ")
   if (guess < 0 | guess > 6):
      print "Please enter a valid cell number!"
   else:   
      guesses = guesses + 1;
   if (guess == location1 | guess == location2 | guess == location3):
      print "HIT!"
      hits = hits + 1
      if (hits == 3):
        isSunk = True
        print "You sank my battleship!"
      else:   
        print "MISS!"
stats = "You took " + guesses + " guesses to sink the battleship, " + "which means your shooting  accuracy was " + (3/guesses)
print stats

我得到的错误是:

Traceback (most recent call last):
  File "battleship.py", line 13, in <module>
    if (guess < 0 | guess > 6):
TypeError: unsupported operand type(s) for |: 'int' and 'str'

我该如何解决这个问题？

Answer 1

在 Python 中 | 是二元或。您应该像这样使用 或 运算符

if guess == location1 or guess == location2 or guess == location3:

而且这一行也得改

if (guess < 0 | guess > 6):

到

if guess < 0 or guess > 6:

引自Binary bit-wise operator documentation ,

The | operator yields the bitwise (inclusive) OR of its arguments, which must be plain or long integers. The arguments are converted to a common type.

但是，通常这个语句是这样写的

if guess in (location1, location2, location3):

此外，raw_input 返回一个字符串。所以你需要像这样将它显式转换为 int

guess = int(raw_input("Ready, aim, fire! (enter a number from 0-6): "))

请注意，在 Python 中您不需要 ; 来标记语句的结束。