python - 合并到不同的词典

Question

我有两个这样的字典列表:

dic1 = [{'Age': 8, 'Pets Name': 'Felix', 'Species': 'Cat'}, {'Age': 57, 'Pets Name': 'Michelangelo', 'Species': 'Tortoise'}, {'Age': 12, 'Pets Name': 'Rantanplan', 'Species': 'Dog'}, {'Age': '2', 'Pets Name': 'Nemo', 'Species': 'Fish'}, {'Age': '45', 'Pets Name': 'Leonardo', 'Species': 'Tortoise'}, {'Age': 9, 'Pets Name': 'Milo', 'Species': 'Dog'}, {'Age': 57, 'Pets Name': 'Raphael', 'Species': 'Tortoise'}, {'Age': '4', 'Pets Name': 'Dory', 'Species': 'Fish'}]
dic2 = [{'Pets Names': 'Michelangelo', "Owner's Names": 'Ana'}, {'Pets Names': 'Dory', "Owner's Names": 'Eva'}, {'Pets Names': 'Rantanplan', "Owner's Names": 'Ada'}, {'Pets Names': 'Leonardo', "Owner's Names": 'Ana'}, {'Pets Names': 'Felix', "Owner's Names": 'Eva'}, {'Pets Names': 'Raphael', "Owner's Names": 'Ana'}, {'Pets Names': 'Nemo', "Owner's Names": 'Eva'}]

我需要制作第三个字典列表，作为(字典的)键，主人的名字，以及他们各自宠物的年龄值。例如，给定上面的两个列表，输出应该是:

dic3 = [{'Ana': [57, 45, 57]}, {'Eva': [4, 8, 2]}, {'Ada': [12]}]

主要目标是获取每个主人的宠物年龄的平均值，但我认为我可以在获得所需的指令后自己完成。到目前为止我只有这个:

def merge_dicts(dic1,dic2):

   name = [li['Pets Name'] for li in dic1]
   age = [li['Age'] for li in dic1]
   owenrsName = [li["Owner's Names"] for li in dic2]

这为我提供了宠物名称、年龄和主人姓名的列表，但我不知道它是否与最终功能相​​关。

提前致谢。

Answer 1

dic1 = [{'Age': 8, 'Pets Name': 'Felix', 'Species': 'Cat'}, {'Age': 57, 'Pets Name': 'Michelangelo', 'Species': 'Tortoise'}, {'Age': 12, 'Pets Name': 'Rantanplan', 'Species': 'Dog'}, {'Age': '2', 'Pets Name': 'Nemo', 'Species': 'Fish'}, {'Age': '45', 'Pets Name': 'Leonardo', 'Species': 'Tortoise'}, {'Age': 9, 'Pets Name': 'Milo', 'Species': 'Dog'}, {'Age': 57, 'Pets Name': 'Raphael', 'Species': 'Tortoise'}, {'Age': '4', 'Pets Name': 'Dory', 'Species': 'Fish'}]
dic2 = [{'Pets Names': 'Michelangelo', "Owner's Names": 'Ana'}, {'Pets Names': 'Dory', "Owner's Names": 'Eva'}, {'Pets Names': 'Rantanplan', "Owner's Names": 'Ada'}, {'Pets Names': 'Leonardo', "Owner's Names": 'Ana'}, {'Pets Names': 'Felix', "Owner's Names": 'Eva'}, {'Pets Names': 'Raphael', "Owner's Names": 'Ana'}, {'Pets Names': 'Nemo', "Owner's Names": 'Eva'}]



def merge_dicts(dic1,dic2):
    dict3= {}
    result = []
    name = [li['Pets Name'] for li in dic1]
    age = [li['Age'] for li in dic1]
    owenrsName = [li["Owner's Names"] for li in dic2]


    for d2 in dic2:

       pname = d2['Pets Names']
       oname = d2["Owner's Names"]

       if oname not in dict3:
            dict3[oname] = []

       for d1 in dic1:
           if d1['Pets Name'] == pname:
               dict3[oname].append(d1['Age'])
    for key,value in dict3.items():
        result.append({key:value})

    print(result)


merge_dicts(dic1,dic2)

对/对

[{'Ada': [12]}, {'Eva': ['4', 8, '2']}, {'Ana': [57, '45', 57]}]