javascript - JSON回调问题

Question

如何获取像这样的 JSON url 数据？

http://api.rottentomatoes.com/api/public/v1.0/movies/770672122/cast.json?apikey=Removed_My_API_Key '

当我像这样复制并粘贴数据时

var titles = {
    "cast": [{
        "id": "162664630",
            "name": "Sylvester Stallone",
            "characters": ["Barney Ross"]
    }, {
        "id": "162653720",
            "name": "Jason Statham",
            "characters": ["Lee Christmas"]
    }, {
        "id": "162652223",
            "name": "Jet Li",
            "characters": ["Yin Yang"]
    }, {
        "id": "162664307",
            "name": "Dolph Lundgren",
            "characters": ["Gunnar Jensen"]
    }, {
        "id": "162670654",
            "name": "Chuck Norris",
            "characters": ["Booker"]
    }, {
        "id": "326392465",
            "name": "Terry Crews",
            "characters": ["Hale Caesar"]
    }, {
        "id": "770731413",
            "name": "Randy Couture",
            "characters": ["Toll Road"]
    }, {
        "id": "770833479",
            "name": "Liam Hemsworth",
            "characters": ["Billy the Kid"]
    }, {
        "id": "770704326",
            "name": "Scott Adkins",
            "characters": ["Hector"]
    }, {
        "id": "770670020",
            "name": "Nan Yu",
            "characters": ["Maggie"]
    }, {
        "id": "162670708",
            "name": "Jean-Claude Van Damme",
            "characters": ["Jean Vilain"]
    }, {
        "id": "162652509",
            "name": "Bruce Willis",
            "characters": ["Mr. Church"]
    }, {
        "id": "162662233",
            "name": "Arnold Schwarzenegger",
            "characters": ["Trench"]
    }, {
        "id": "489251774",
            "name": "Amanda Ooms",
            "characters": ["Pilar"]
    }, {
        "id": "377608335",
            "name": "Charisma Carpenter",
            "characters": ["Lacy"]
    }, {
        "id": "771417014",
            "name": "Nikolette Noel",
            "characters": ["Sophia"]
    }],
        "links": {
        "rel": "http://api.rottentomatoes.com/api/public/v1.0/movies/771238417.json"
    }
},
star,
staring = [];

for (star = 0; star < titles.cast.length; star++) {
    staring.push(titles.cast[star].name + ' as ' + titles.cast[star].characters[0]);
}

document.getElementById('Credits').innerHTML = staring.join(', ');

它使用上面的代码工作，我正在尝试弄清楚如何直接从 URL 本身获取它。

我尝试过以下方法

var movieUrl = 'http://api.rottentomatoes.com/api/public/v1.0/movies/770672122/cast.json?apikey=Removed_My_API'

$(document).ready(function() {

  $.ajax({
    url: moviesSearchUrl + encodeURI(query),
    dataType: "jsonp",
    success: searchCallback
  });
});


function searchCallback(data) {
 var titles = data.cast    
star,
staring = [];

for (star = 0; star < titles.cast.length; star++) {
    staring.push(titles.cast[star].name + ' as ' + titles.cast[star].characters[0]);
}

document.getElementById('Credits').innerHTML = staring.join(', ');}

使用这个 JS Fiddle http://jsfiddle.net/6yYYZ/ ，有人可以帮忙吗？

Answer 1

您的代码中有很多错误，我部分修复了它，以便您取回数据

最重要的修复是你的ajax调用中的url是错误的，我修复了这个问题。

var movieUrl = 'http://api.rottentomatoes.com/api/public/v1.0/movies/770672122/cast.json?apikey=API_KEY'

$(document).ready(function() {

  $.ajax({
    url: movieUrl,
    dataType: "jsonp",
    success: searchCallback
  });
});


function searchCallback(data) {

    console.log(data); // do stuff with your json here

}

http://jsfiddle.net/6yYYZ/5/