ios - 在 Objective-C 中传递参数

Question

我有一个请求 URL 的 sharedClient

#define BASE_URL @"http://myurl.com"

+ (id)sharedClient {
static MyClient *__instance;
static dispatch_once_t onceToken;
dispatch_once(&onceToken, ^{
    NSURL *baseUrl = [NSURL URLWithString:BASE_URL];
    __instance = [[MyClient alloc] initWithBaseURL:baseUrl];
});
    return __instance;
}

然后我在按下按钮时在 View Controller 中调用它

id params = @{
              @"username": self.usernameField.text,
              @"password": self.passwordField.text
              };

[[MyClient sharedClient]getPath:@"/users/current.json"
                           parameters:params
                              success:^(AFHTTPRequestOperation *operation, id responseObject) {
                                  NSString *authToken = [responseObject objectForKey:@"api_key"];
                                  [self.credentialStore setAuthToken:authToken];

                                  [SVProgressHUD dismiss];

                                  [self dismissViewControllerAnimated:YES completion:nil];
                              } failure:^(AFHTTPRequestOperation *operation, NSError *error) {
                                  NSLog(@"%ld", (long)operation.response.statusCode);
                                  if (operation.response.statusCode == 500) {
                                      [SVProgressHUD showErrorWithStatus:@"Something went wrong!"];
                                  } else {
                                      NSData *jsonData = [operation.responseString dataUsingEncoding:NSUTF8StringEncoding];
                                      NSDictionary *json = [NSJSONSerialization JSONObjectWithData:jsonData
                                                                                           options:0
                                                                                             error:nil];
                                      NSString *errorMessage = [json objectForKey:@"error"];
                                      [SVProgressHUD showErrorWithStatus:errorMessage];
                                  }
                              }];

这段代码工作正常，但我的问题是我尝试访问的 API 有点奇怪。您必须在 url 之前传递用户名和密码。像这样

http://username:password@myurl.com

我将如何在 URL 的 http 之前传递参数？

Answer 1

NSURLComponents *urlComponents = [NSURLComponents componentsWithString:BASE_URL];
urlComponents.user = @"user";
urlComponents.password = @"pass";
NSURL *url = urlComponents.URL;

然后只需使用 url 来初始化您的客户端。