python - 艰难地学习 python 练习 35 帮助

Question

出于某种原因，当游戏进入黄金房间时无法正常运行。当我输入任何数字时，我都会收到死亡消息“伙计，学会输入数字”

谢谢

from sys import exit

def gold_room():
    print 'this room is full of gold, how much do you take?'

    next = raw_input('> ')
    if '0' in next or '1' in next:
        how_much = int(next)
    else:
        dead('man, learn how to type a number')


    if how_much < 50:
        print 'nice! your not too greedy. you win!'
        exit(0)
    else:
        dead('you greedy bastard!')


def bear_room():
    print 'there is a bear here.'
    print 'the bear has a bunch of honey'
    print 'the fat bear is in fromt of another door'
    print 'how are you going to move the bear?'
    bear_moved = False


    while True:
        next = raw_input('> ')

        if next == 'take honey':
            dead('the bear looks at you then pimp slaps you in the face')
        elif next == 'taunt bear' and not bear_moved:
            print 'the bear has moved from the door now. you can go through.'
            bear_moved = True
        elif next == 'taunt bear' and bear_moved:
            dead('the bear gets pissed off and chews your crotch off')
        elif next == 'open door' and bear_moved:
            gold_room()
        else:
            print 'i have no idea what that means.'


def bolofumps_room():
    print 'here you see the great evil bolofump'
    print 'he, it whatever stares at you and you go insane'
    print 'do you flee for your life or eat your head?'

    next = raw_input('> ')
    if 'flee' in next:
        start()
    elif 'head' in next:
        dead('well, that was tasty!')
    else:
        bolofumps_room()

def dead(why):
    print why, 'good job!'
    exit(0)


def start():
    print 'you are in a dark room'
    print 'there is a door to your left and right'
    print 'which one do you take?'

    next = raw_input('> ')

    if next == 'left':
        bear_room()
    elif next == 'right':
        bolofumps_room()
    else:
        dead('you stumble around the room until you starve to death')


start()

编辑:输入 1 有效，但 2 无效

Answer 1

您在 gold_room 中执行此操作:

next = raw_input('> ')
if '0' in next or '1' in next:
    how_much = int(next)
else:
    dead('man, learn how to type a number')

它只检查 下一个是“0”还是下一个是“1”，所以“2”不起作用并不奇怪，对吧？

你想要的是沿着这些线

next = raw_input('> ')
try:
    how_much = int(next)
except ValueError:
    dead('man, learn how to type a number')

无异常(exception)地执行此操作也是可能的，但请记住，避免像异常(exception)一样重要和基本的事情是一个非常糟糕的主意。我希望这本书至少能在以后阐明这一点。

无论如何，我们知道 int 只接受数字，所以我们只检查一下:

if next.isdigit():
    how_much = int(next)