gpt4 book ai didi

ios - xCode 不允许添加对象

转载 作者:行者123 更新时间:2023-11-28 19:56:19 25 4
gpt4 key购买 nike

这里绝对是新手。我正在尝试使用几种不同的来源自学 Xcode。在我当前的类(class)中,我只是试图将字符串中的每个单词大写。出于某种原因,我没有使用 addObject 的选项,即使我已经求助于逐行复制书中的内容!这是我正在使用的代码,我只是将其输入到 ViewController.m 中。我没有接触过头文件。

#import "ViewController.h"
@interface ViewController ()

@end
@implementation ViewController

- (void)viewDidLoad {
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.


NSString *myString = @"How much wood could a woodchuck chuck";

NSArray *wordsInSentence = [myString componentsSeparatedByString:@" "];
NSLog(@"%@", wordsInSentence);

NSMutableArray *capitalizedWords = [[NSMutableArray alloc] init];

for (int word =0; word < [wordsInSentence count]; word++)
{

NSString *uncapitalizedWords = [wordsInSentence objectAtIndex:word];
NSString *capitalizedWords = [uncapitalizedWords capitalizedString];
[capitalizedWords addObject:capitalizedWords];
}
NSLog(@"%@", capitalizedWords);
}

- (void)didReceiveMemoryWarning {
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}

@end

我的问题是 [大写词 addObject:大写词];当我开始输入时,它甚至没有在下拉框中显示 addObject 作为选项,我唯一的选项是 addObserver。

非常感谢任何帮助,谢谢

最佳答案

问题是您有两个具有相同名称的变量,capitalizedWords。一个是可变数组,另一个是字符串。因此,当您在 for 循环中使用 capitalizedWords 时,它使用的是字符串再现。我建议重命名字符串变量,例如,替换:

NSString *uncapitalizedWords = [wordsInSentence objectAtIndex:word];
NSString *capitalizedWords = [uncapitalizedWords capitalizedString];
[capitalizedWords addObject:capitalizedWords];

NSString *uncapitalizedWord = [wordsInSentence objectAtIndex:word];  // renaming this isn't critical, but using singular case makes it more clear
NSString *capitalizedWord = [uncapitalizedWord capitalizedString]; // renaming this fixes the problem
[capitalizedWords addObject:capitalizedWord];

关于ios - xCode 不允许添加对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26202806/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com