python - 仅显示回溯的第一行和最后一行

Question

我用 python 构建了一个小的内部 DSL。我正在使用 assert 进行验证。如果最终用户输入了错误的参数，dsl 应该报告错误。目前这看起来像这样:

Traceback (most recent call last):
  File "tests/maskedtimefilter_test/FilterDSL_test.py", line 63, in test_dsl_validation
    input(0): self.regular
  File "/Users/sh/reetz/pythonpath/maskedtimedata/maskedtimefilter.py", line 885, in __lshift__
    kwargs = self.dsl_validation(kwargs)
  File "/Users/sh/reetz/pythonpath/maskedtimedata/maskedtimefilter.py", line 1483, in dsl_validation
    check_if_valid(parameter)
  File "/Users/sh/reetz/pythonpath/maskedtimedata/dsl.py", line 47, in kernel_a
    def kernel_a (x): assert isinstance(x, (list, tuple, np.ndarray)), "kernel must be a list."
AssertionError: kernel must be a list.

但最终用户是工程师，而不是计算机科学家。因此，最小的 Traceback 很方便。 是否可以将 Traceback 缩小到基本信息(哪里失败了，原因是什么)像这样？/强>

Traceback (most recent call last):
  File "tests/maskedtimefilter_test/FilterDSL_test.py", line 63, in test_dsl_validation
    input(0): self.regular
AssertionError: kernel must be a list.

我很不情愿地想使用普通打印件!

Answer 1

为什么不将回溯数据作为数组返回并从中返回呢？

import traceback
try:
     codethatwillthrowanexception()
except:
     exceptiondata = traceback.format_exc().splitlines()
     exceptionarray = [exceptiondata[-1]] + exceptiondata[1:-1]