ios - 解析 JSON 时无法识别的选择器

Question

下面的照片是我尝试从 URL 读取的 JSON 脚本的屏幕截图。在下面的代码部分，我设法获取了“name”属性并将其分配给“name”NSString 对象，但是当我尝试对“address”执行相同操作时，出现以下错误:

[__NSCFDictionary objectAtIndexedSubscript:]: unrecognized selector sent to instance 0x174260980
*** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[__NSCFDictionary objectAtIndexedSubscript:]: unrecognized selector sent to instance 0x174260980'

我在“场所”内的操作方式与在“位置”内的操作方式有何区别？我尝试了很多不同的方法来做到这一点，有些包括数组，但似乎没有任何效果。

NSURL *url = [NSURL URLWithString:urlString];

NSData *jsonData = [NSData dataWithContentsOfURL:url];
NSError *error = nil;
NSDictionary *dataDictionary = [NSJSONSerialization JSONObjectWithData:jsonData options:0 error:&error];

NSDictionary *responseDictionary = [dataDictionary objectForKey:@"response"];
NSDictionary *venueDictionary = [responseDictionary objectForKey:@"venues"];

for (NSDictionary *dict in venueDictionary) {
    NSLog(@"%@", dict);
    NSString *name = [dict objectForKey:@"name"];
    NSDictionary *locationDictionary = [dict objectForKey:@"location"];
    for (NSDictionary *locationDict in locationDictionary) {
        NSString *address = [locationDict objectForKey:@"address"];
        NSLog(@"%@", address);
    }
}

Answer 1

您期望“location”键指向一个数组，但事实并非如此。它指向一个对象，摆脱 for (NSDictionary *locationDict in locationDictionary) { 并只是从 locationDictionary 中提取地址。