python - 从列表 Python 中获取所有可能对的差异

Question

我有一个未指定数字的 int 列表。我想找到列表中匹配特定值的两个整数之间的差异。

#Example of a list
intList = [3, 6, 2, 7, 1]

#This is what I have done so far

diffList = []

i = 0
while (i < len(intList)):
    x = intList[i]

    j = i +1
    while (j < len(intList)):
        y = intList[j]

        diff = abs(x-y)
        diffList.append(diff)

        j += 1
    i +=1

#Find all pairs that has a difference of 2
diff = diffList.count(2)
print diff

有更好的方法吗？

编辑:对代码进行了更改。这就是我想要做的。我想知道的是除了循环我还能用什么。

Answer 1

似乎是 itertools.combinations 的工作

from itertools import combinations
for a, b in combinations(intList, 2):
   print abs(a - b)

如果你愿意的话，你甚至可以把它变成一个列表理解:)

[abs(a -b) for a, b in combinations(intList, 2)]