ios - NSExpression 使用 sqrt : function results in NSInvalidArgumentException

Question

我得到一个 NSInvalidArgumentException:

*** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Unsupported function type passed to SQL store'

当尝试使用 NSExpression 对使用“multiply:by:”函数的嵌套 NSExpression 求平方根时。

我的代码是这样的:

NSManagedObjectContext *context=[[BDCoreDataController sharedController] mainManagedObjectContext];
NSFetchRequest *theRequest=[[NSFetchRequest alloc] init];

[theRequest setEntity:[NSEntityDescription entityForName:@"BDCompanyEntity" inManagedObjectContext:context]];
theRequest.resultType=NSDictionaryResultType;

NSExpression *constantExpression=[NSExpression expressionForConstantValue:[NSNumber numberWithDouble:22.5]];
NSExpression *firstKeyPath=[NSExpression expressionForKeyPath:@"epsTTM"];
NSExpression *secondKeyPath=[NSExpression expressionForKeyPath:@"bookValuePerShare"];

NSExpression *firstMultiplyExpression=[NSExpression expressionForFunction:@"multiply:by:" arguments:@[firstKeyPath,secondKeyPath]];

NSExpression *secondMultiplyExpression=[NSExpression expressionForFunction:@"multiply:by:" arguments:@[firstMultiplyExpression,constantExpression]];

NSExpression *sqrtExpression=[NSExpression expressionForFunction:@"sqrt:" arguments:@[secondMultiplyExpression]];

NSExpressionDescription *expressionDescription=[[NSExpressionDescription alloc] init];
[expressionDescription setName:@"grahamNumber"];
[expressionDescription setExpression:sqrtExpression];
[expressionDescription setExpressionResultType:NSDoubleAttributeType];

[theRequest setPropertiesToFetch:@[expressionDescription,@"name"]];

NSError *fetchError;
NSArray *grahams=[context executeFetchRequest:theRequest error:&fetchError];

通过尝试评估嵌套的“multiply:by:”来执行获取可以很好地处理以下代码:

NSManagedObjectContext *context=[[BDCoreDataController sharedController] mainManagedObjectContext];
NSFetchRequest *theRequest=[[NSFetchRequest alloc] init];

[theRequest setEntity:[NSEntityDescription entityForName:@"BDCompanyEntity" inManagedObjectContext:context]];
theRequest.resultType=NSDictionaryResultType;

NSExpression *constantExpression=[NSExpression expressionForConstantValue:[NSNumber numberWithDouble:22.5]];
NSExpression *firstKeyPath=[NSExpression expressionForKeyPath:@"epsTTM"];
NSExpression *secondKeyPath=[NSExpression expressionForKeyPath:@"bookValuePerShare"];

NSExpression *firstMultiplyExpression=[NSExpression expressionForFunction:@"multiply:by:" arguments:@[firstKeyPath,secondKeyPath]];

NSExpression *secondMultiplyExpression=[NSExpression expressionForFunction:@"multiply:by:" arguments:@[firstMultiplyExpression,constantExpression]];

NSExpressionDescription *expressionDescription=[[NSExpressionDescription alloc] init];
[expressionDescription setName:@"grahamNumber"];
[expressionDescription setExpression: secondMultiplyExpression];
[expressionDescription setExpressionResultType:NSDoubleAttributeType];

[theRequest setPropertiesToFetch:@[expressionDescription,@"name"]];

NSError *fetchError;
NSArray *grahams=[context executeFetchRequest:theRequest error:&fetchError];

起初我认为可能是“sqrt”NSExpression 与嵌套的 NSExpression 有问题。所以我只尝试了一个常量 NSExpression。以下代码尝试仅对 sqrt NSExpression 中的常量求值。它会导致相同的 NSInvalidArguementException

NSManagedObjectContext *context=[[BDCoreDataController sharedController] mainManagedObjectContext];
NSFetchRequest *theRequest=[[NSFetchRequest alloc] init];

[theRequest setEntity:[NSEntityDescription entityForName:@"BDCompanyEntity" inManagedObjectContext:context]];
theRequest.resultType=NSDictionaryResultType;

NSExpression *constantExpression=[NSExpression expressionForConstantValue:[NSNumber numberWithDouble:22.5]];

NSExpression *sqrtExpression=[NSExpression expressionForFunction:@"sqrt:" arguments:@[constantExpression]];

NSExpressionDescription *expressionDescription=[[NSExpressionDescription alloc] init];
[expressionDescription setName:@"grahamNumber"];
[expressionDescription setExpression:sqrtExpression];
[expressionDescription setExpressionResultType:NSDoubleAttributeType];

[theRequest setPropertiesToFetch:@[expressionDescription,@"name"]];

NSError *fetchError;
NSArray *grahams=[context executeFetchRequest:theRequest error:&fetchError];

任何可能导致问题的想法？

谢谢

工具人

Answer 1

并非所有对 NSExpression 有效的表达式在使用 SQLite 存储时从 Core Data 中获取时都有效。不幸的是，sqrt: 不支持这种用途。它可能会与二进制存储一起工作，但这会失去 Core Data 的许多优势(例如，这意味着将所有数据一次加载到内存中)。

特别令人恼火的是，没有文档列表表明哪些函数支持与 Core Data 一起使用。但错误消息是完全正确的:尽管此函数对 NSExpression 使用有效，但对 SQLite 持久存储无效。