unit-testing - 在 laravel 测试中调用命名路由

Question

考虑以下几点:

<?php

use Illuminate\Foundation\Testing\WithoutMiddleware;
use Illuminate\Foundation\Testing\DatabaseMigrations;
use Illuminate\Foundation\Testing\DatabaseTransactions;

class HomeRouteTest extends TestCase
{
    public function testVisitTheHomePage()
    {
        $response = $this->call('GET', '/');
        $this->assertEquals(200, $response->status());

    }

    public function testVisitTheAboutPage()
    {
        $response = $this->call('GET', '/about');
        $this->assertEquals(200, $response->status());
    }
}

有没有，我没有看到文档 >.>，做类似的事情:

$response = $this->call('GET', 'home.about');
$this->assertEquals(200, $response->status());

或者......你是这样做的吗？

我得到的错误是:

vagrant@scotchbox:/var/www$ phpunit
PHPUnit 4.8.21 by Sebastian Bergmann and contributors.

FF

Time: 3.41 seconds, Memory: 14.25Mb

There were 2 failures:

1) HomeRouteTest::testVisitTheHomePage
Failed asserting that 404 matches expected 200.

/var/www/tests/HomeRouteTest.php:12

2) HomeRouteTest::testVisitTheAboutPage
Failed asserting that 404 matches expected 200.

/var/www/tests/HomeRouteTest.php:19

FAILURES!
Tests: 2, Assertions: 2, Failures: 2.

Answer 1

据我所知，此解决方案适用于任何 Laravel 5 版本。特别是 Laravel 5.4+ 与此处提到的其他解决方案不同。

如果你的命名路由有参数，你可以这样做:

$response = $this->get(route('users.show', [
    'user' => 3,
]));

$response->assertStatus(200);

如果你的命名路由没有参数那么你可以这样做:

$response = $this->get(route('users.index'));

$response->assertStatus(200);

漂亮而简单。