scala - 在规范之前和之后执行代码

Question

我有几个案例的简单说明:

class MySpec extends Specification {

  "Something" should {

    "case 1" in {
      ...
    }

    "case 2" in {
      ...
    }
  }
}

现在我需要启动应用程序，运行所有案例，然后关闭应用程序。启动/停止应用程序非常耗时，我不希望它在每种情况下都发生。

如何在案例开始之前和所有案例结束之后运行代码？

Answer 1

我根据 cmbaxter 的回答提出了以下解决方案。

import org.specs2.specification.Step

trait BeforeAllAfterAll extends Specification {
  // see http://bit.ly/11I9kFM (specs2 User Guide)
  override def map(fragments: =>Fragments) = 
    Step(beforeAll) ^ fragments ^ Step(afterAll)

  protected def beforeAll()
  protected def afterAll()
}

然后在Specification中混合BeforeAllAfterAll并实现beforeAll和afterAll方法:

class MySpec extends Specification with BeforeAllAfterAll {

  def beforeAll() {
    println("Doing setup work...")
  }

  def afterAll() {
    println("Doing shutdown work...")
  }

  "Something" should {

    "case 1" in {
      ...
    }

    "case 2" in {
      ...
    }
  }
}

最后，提取初始化以在规范之间共享:

trait InApplication extends BeforeAllAfterAll {
  def beforeAll() {
    println("Doing setup work...")
  }

  def afterAll() {
    println("Doing shutdown work...")
  }
}

class MySpec extends Specification with InApplication {

  "Something" should {

    "case 1" in {
      ...
    }

    "case 2" in {
      ...
    }
  }
}