javascript - 如何测试 Jasmine 中的方法是否只被调用一次而不是第二次？

Question

我正在测试应该调用方法一次并防止任何后续调用 Jasmine 的机制，我可以通过附加断点看到该方法没有被第二次调用但是 Jasmine 测试失败。我认为这与 spy 没有设计用于多次检查有关。
什么是给定情况的适当解决方案？

JSfiddle of Code that is being tested我不知道如何正确地进行 jasmine 测试 jsfiddle(我使用的 Jasmine 版本是 1.3.1，而测试模板是 1.2.0)。

测试看起来像这样:

 it("Invoking OnPreQuery will add event listener for OnTheMoveViewPreLoad event. Triggering OnTheMoveViewPreLoad twice will call getChildrenForMasterRecordList only first time", function () {
            AddTreeSettingsObjectToBC({ bc: bc, Tree: { IncludeChildren: true} });
            ComposeMockPageObjWithObservableFieldsWithChildren();
            var preQuerySpy = spyOnEvent(onTheMove.PageDataRoles, 'OnPreQuery');
            $(onTheMove.PageDataRoles).trigger('OnPreQuery', { knockoutContextName: 'bc' });
            expect('OnPreQuery').toHaveBeenTriggeredOn(onTheMove.PageDataRoles);
            expect(preQuerySpy).toHaveBeenTriggered();
            var getChildrenForMasterRecordListSpy = spyOn(window, 'getChildrenForMasterRecordList');
            $(onTheMove.PageDataRoles).trigger('OnTheMoveViewPreLoad', { knockoutContextName: 'bc' });
            expect(getChildrenForMasterRecordListSpy).toHaveBeenCalled();
            $(onTheMove.PageDataRoles).trigger('OnTheMoveViewPreLoad', { knockoutContextName: 'bc' });
            expect(getChildrenForMasterRecordListSpy).not.toHaveBeenCalled();
        });

正在测试的代码:HTML

<div data-role="page"></div>

Javascript

var onTheMove = function(){};
$.extend(onTheMove,{
    NullValue : "null",
    PageDataRoles : 'div[data-role="page"], div[data-role="dialog"]',
    OnTheMovePrefix : 'OnTheMove_'
    });

$(document).on('OnPreQuery', onTheMove.PageDataRoles, function (e, options) {
    var isChildAttachmentQueued = true;
    var knockoutContextName = options.knockoutContextName;
    if (TreeEnabled(knockoutContextName)) {
        var isModelReadyToAttachChildren = function () {
            var isReady = false;
            if (PageObj[knockoutContextName] != undefined) {
                isReady = (PageObj[knockoutContextName]().length > 0) && isChildAttachmentQueued;
            }

            return isReady;
        };
        var treeSettings = eval(knockoutContextName).Tree;
        treeSettings.knockoutContextName = knockoutContextName;
        $(onTheMove.PageDataRoles).on('OnTheMoveViewPreLoad', function (e, options) {
            if (isModelReadyToAttachChildren()) {
                getChildrenForMasterRecordList({
                    parentTable: eval(knockoutContextName).primaryTableName,
                    knockoutContextName: treeSettings.knockoutContextName,
                    parentIdColumn: treeSettings.ParentIdColumn,
                    masterIdColumn: treeSettings.MasterIdColumn
                });
                isChildAttachmentQueued = false;
            }
        });
    }
});
function getChildrenForMasterRecordList(options) {
    console.log('beep');
}

Answer 1

toHaveBeenCalledTimes(1)

现在让这变得容易多了。

 expect(yourSpy).toHaveBeenCalledTimes(1);