Python:通过字典比较两个同义词

Question

我有一个同义词字典:

synonym = {"this": ["this", "same"],
           "all": ["all", "any", "*"],
           "alluptolastyear": ["alluptolastyear", "uptolastyear"],
           "dekadbefore": ["dekadbefore", "lastdekad", "formerdekad", "precedingdekad"],
           "dekadafter": ["dekadafter", "nextdekad", "followingdekad"],
           "yearbefore": ["yearbefore", "lastyear", "formeryear"],
           "monthbefore": ["monthbefore", "lastmonth", "precedingmonth"]}

每个数组存储同义词，通过键引用。我从一个 XML 文件中读取了两个字符串，并尝试比较它们。

例如:

• "this" 和 "same" 是等价的(同义词)
• '"lastyear"' 和 '"formeryear"' 相等(同义词)
• "all" 和"nextdekad" 不同
• 当然，每个键值都在其对应的数组中找到，因此每个键都是其数组字符串的同义词。

有人可以帮助我使用同义词字典对这些字符串进行 pythonic 比较吗？

Answer 1

试试这个:

def are_sinonims(a, b):
    return a in synonym.get(b,[]) or b in synonym.get(a,[]) or any(a in synonym[k] and b in synonym[k] for k in synonym)

此外，我们可以将 a in synonym[k] and b in synonym[k] for k in synonym 重写为 a in words 和 b in words for words in synonym。 values() 这样:

def are_sinonims(a, b):
    return a in synonym.get(b,[]) \
           or b in synonym.get(a,[]) \
           or any(a in words and b in words for words in synonym.values())