python - 检查python中目录的权限

Question

我想要一个给定目录的 python 程序，它将返回该目录中具有 775 (rwxrwxr-x) 权限的所有目录

谢谢!

Answer 1

这两个答案都没有递归，尽管还不完全清楚这就是 OP 想要的。这是一种递归方法(未经测试，但您明白了):

import os
import stat
import sys

MODE = "775"

def mode_matches(mode, file):
    """Return True if 'file' matches 'mode'.

    'mode' should be an integer representing an octal mode (eg
    int("755", 8) -> 493).
    """
    # Extract the permissions bits from the file's (or
    # directory's) stat info.
    filemode = stat.S_IMODE(os.stat(file).st_mode)

    return filemode == mode

try:
    top = sys.argv[1]
except IndexError:
    top = '.'

try:
    mode = int(sys.argv[2], 8)
except IndexError:
    mode = MODE

# Convert mode to octal.
mode = int(mode, 8)

for dirpath, dirnames, filenames in os.walk(top):
    dirs = [os.path.join(dirpath, x) for x in dirnames]
    for dirname in dirs:
        if mode_matches(mode, dirname):
            print dirname

stdlib 文档中描述了类似的内容 stat .