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javascript - 使用 Underscorejs 从 json 中提取值

转载 作者:行者123 更新时间:2023-11-28 19:24:21 25 4
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我有一个 json,需要从中过滤 name 值与传递的输入匹配的对象,然后从相应的 links< 中提取 href 对象的 ref 值为 self。我附上代码片段以及我的过滤方法。我正在使用 Underscore.js

var jsonObj = [
{
"links": [
{
"rel": "self",
"href": "http://hostname:port/state/644444",
"variables": [],
"variableNames": [],
"templated": false
},
{
"rel": "city",
"href": "http://hostname:port/city/6184",
"variables": [],
"variableNames": [],
"templated": false
}
],
"stateId": 65986,
"countyId": 6184,
"name": "AAATest",
"population": 20000,
"location": "SFS CSR"
},
{
"links": [
{
"rel": "self",
"href": "http://hostname:port/state/65987",
"variables": [],
"variableNames": [],
"templated": false
},
{
"rel": "city",
"href": "http://hostname:port/city/6184",
"variables": [],
"variableNames": [],
"templated": false
}
],
"stateId": 65987,
"countyId": 6184,
"name": "2k8std511",
"population": 20000,
"location": "SFS CSR"
}
]

var keywords='2k8std511';

var filtered = _.filter(jsonObj, function (item) {
return (_.contains('2k8std511', item['name']));
});
console.log(_.chain(jsonObj)
.pluck("links")
.flatten()
.value());

请告诉我如何根据给定关键字进行过滤:

示例输入:AAATest 预期输出:[href:'http://hostname:port/state/644444 ']

问候,普拉迪普

最佳答案

下划线解决方案:

var jsonObj = [{
"links": [{
"rel": "self",
"href": "http://hostname:port/state/644444",
"variables": [],
"variableNames": [],
"templated": false
}, {
"rel": "city",
"href": "http://hostname:port/city/6184",
"variables": [],
"variableNames": [],
"templated": false
}],
"stateId": 65986,
"countyId": 6184,
"name": "AAATest",
"population": 20000,
"location": "SFS CSR"
}, {
"links": [{
"rel": "self",
"href": "http://hostname:port/state/65987",
"variables": [],
"variableNames": [],
"templated": false
}, {
"rel": "city",
"href": "http://hostname:port/city/6184",
"variables": [],
"variableNames": [],
"templated": false
}],
"stateId": 65987,
"countyId": 6184,
"name": "2k8std511",
"population": 20000,
"location": "SFS CSR"
}]

var filtername = 'AAATest';
var answer = _.chain(jsonObj)
.filter(function(obj) {
return obj.name === filtername;
})
.map(function(obj) {
return obj.links
})
.first()
.filter(function(obj) {
return obj.rel === 'self'
})
.map(function(obj) {
return obj.href
})
.value();
console.log(answer);
<script src="http://underscorejs.org/underscore-min.js"></script>

关于javascript - 使用 Underscorejs 从 json 中提取值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28163514/

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