gpt4 book ai didi

php - 适用于 iOS 的简单 PHP/MySQL Web 服务

转载 作者:行者123 更新时间:2023-11-28 19:23:55 25 4
gpt4 key购买 nike

基于:http://www.raywenderlich.com/2941/how-to-write-a-simple-phpmysql-web-service-for-an-ios-app

我的数据库是这样的:id | rw_promo_code_id | email_id |设备编号 |赎回时间

我在 index.php 中试试这个:

// Check for required parameters
if (isset($_POST["rw_app_id"]) && isset($_POST["code"]) && isset($_POST["email_id"]) && isset($_POST["device_id"]) ) {

...........
// Add tracking of redemption
$stmt = $this->db->prepare("INSERT INTO rw_promo_code_redeemed (rw_promo_code_id, email_id, device_id) VALUES (?, ?, ?)");
$stmt->bind_param("is", $id, $email_id, device_id);
$stmt->execute();
$stmt->close();

如果我删除 && isset($_POST["device_id"]) 并制作这一行

$stmt = $this->db->prepare("INSERT INTO rw_promo_code_redeemed 
(rw_promo_code_id, email_id, device_id) VALUES (?, ?, ?)");

$stmt = $this->db->prepare("INSERT INTO rw_promo_code_redeemed
(rw_promo_code_id, email_id) VALUES (?, ?)");

我当然在数据库中正确获取了电子邮件,但不是设备 ID

我怎样才能让这两个值(device_id 和 email_id)显示在数据库中,而不是只有一个?

我在应用中使用这个(这个没有问题)

NSString *emailadrress = email.text;
NSURL *url = [NSURL URLWithString:@"http://localhost:8888/"];
ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:url];
[request setPostValue:@"1" forKey:@"rw_app_id"];
[request setPostValue:code forKey:@"code"];
[request setPostValue:emailadrress forKey:@"email_id"];
[request setPostValue:@"23131" forKey:@"device_id"];
[request setDelegate:self];
[request startAsynchronous];

编辑:这是原始函数:

function redeem() {

// Check for required parameters
if (isset($_POST["rw_app_id"]) && isset($_POST["code"]) && isset($_POST["device_id"])) {

// Put parameters into local variables
$rw_app_id = $_POST["rw_app_id"];
$code = $_POST["code"];
$device_id = $_POST["device_id"];

// Look up code in database
$user_id = 0;
$stmt = $this->db->prepare('SELECT id, unlock_code, uses_remaining FROM rw_promo_code WHERE rw_app_id=? AND code=?');
$stmt->bind_param("is", $rw_app_id, $code);
$stmt->execute();
$stmt->bind_result($id, $unlock_code, $uses_remaining);
while ($stmt->fetch()) {
break;
}
$stmt->close();

// Bail if code doesn't exist
if ($id <= 0) {
sendResponse(400, 'Invalid code');
return false;
}

// Bail if code already used
if ($uses_remaining <= 0) {
sendResponse(403, 'Code already used');
return false;
}

// Check to see if this device already redeemed
$stmt = $this->db->prepare('SELECT id FROM rw_promo_code_redeemed WHERE device_id=? AND rw_promo_code_id=?');
$stmt->bind_param("si", $device_id, $id);
$stmt->execute();
$stmt->bind_result($redeemed_id);
while ($stmt->fetch()) {
break;
}
$stmt->close();

// Bail if code already redeemed
if ($redeemed_id > 0) {
sendResponse(403, 'Code already used');
return false;
}

// Add tracking of redemption
$stmt = $this->db->prepare("INSERT INTO rw_promo_code_redeemed (rw_promo_code_id, device_id) VALUES (?, ?)");
$stmt->bind_param("is", $id, $device_id);
$stmt->execute();
$stmt->close();

// Decrement use of code
$this->db->query("UPDATE rw_promo_code SET uses_remaining=uses_remaining-1 WHERE id=$id");
$this->db->commit();

// Return unlock code, encoded with JSON
$result = array(
"unlock_code" => $unlock_code,
);
sendResponse(200, json_encode($result));
return true;
}
sendResponse(400, 'Invalid request');
return false;

}

编辑:错误

PHP Warning:  mysqli_stmt::bind_param() [<a

href='mysqli-stmt.bind-param'>mysqli-stmt.bind-param]: Number of elements in type definition string doesn't match number of bind variables in /Applications/MAMP/htdocs/index.php on line 134

这是:

$stmt = $this->db->prepare("INSERT INTO rw_promo_code_redeemed (rw_promo_code_id, device_id, email_id) VALUES (?, ?, ?)"); $stmt->bind_param("is", $id, $device_id, $email_id);

最佳答案

得到你...

缺少第三个变量的值类型

$stmt = $this->db->prepare("INSERT INTO rw_promo_code_redeemed (rw_promo_code_id, device_id, email_id) VALUES (?, ?, ?)"); $stmt->bind_param("iss", $id, $device_id, $email_id);

"is" 更改为 "iss" 或 "iis"所需的任何一项。您可以在

上获得有关 bind_param 的更多信息

http://www.php.net/manual/en/mysqli-stmt.bind-param.php

关于php - 适用于 iOS 的简单 PHP/MySQL Web 服务,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6156411/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com