iphone - SQLITE 选择上的 BAD_ACCESS

Question

当我尝试使用我在 iPhone 开发中从本地 SQLITE 数据库中选择的值执行任何操作时，我收到 EXC_BAD_ACCESS。我的功能代码是

-(void) updateFromDB {

// Setup the database object
sqlite3 *database;

// Open DB
if(sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK) {

    NSString *query = [NSString stringWithFormat:@"SELECT MOD_ID FROM MODULE;"];

    //NSLog(@"QUERY: %@",query);

    // Prepare statement
    sqlite3_stmt *statement;
    if(sqlite3_prepare_v2(database, [query UTF8String], -1, &statement, NULL) == SQLITE_OK) {

        // Execute SQL
        while (sqlite3_step(statement) == SQLITE_ROW) {

            // Get MOD_IDs
            NSInteger MOD_ID = sqlite3_column_int(statement, 0);

            NSString *ID = [NSString stringWithFormat:@"%@",MOD_ID];

            //=======================
            // Get Notice Module Data
            //=======================
            if (MOD_ID == 1) {
                self.noticeModule = [[ModuleSetting alloc] initWithID:ID];
            }




        }

    } else {
        NSAssert1(0,@"Error: failed to prepare statement. '%s'", sqlite3_errmsg(database));
    }

    // Release the compiled statement from memory
    sqlite3_finalize(statement);

} else {
    sqlite3_close(database);
    NSAssert1(0,@"Failed to open database. '%s'",sqlite3_errmsg(database));
}
sqlite3_close(database);

}

线路出现异常访问

NSString *ID = [NSString stringWithFormat:@"%@",MOD_ID];

感谢您提供的任何帮助!

Answer 1

%@ 表示对象。但是MOD_ID 似乎是一个整数。所以你的格式应该是%d,

NSString *ID = [NSString stringWithFormat:@"%d", MOD_ID];