javascript - 如何使用 javascript find 方法解析 xml？

Question

我正在使用 JavaScript 解析 xml。

我当前的代码；

xmlDoc = $.parseXML( fnSuccess.__batchResponses[0].response.body ),
            $xml = $( xmlDoc ),
            $errormessage = $xml.find( "message" );

$errormessage.text() 及其返回值:

<code>SY/530</code>
<message xml:lang="en">S:W5:102 0010017899</message>
<innererror>
<transactionid>A831E4E4ADFDF1998E50005056AA3F7A</transactionid>
<timestamp/><Error_Resolution><SAP_Transaction/><SAP_Note/></Error_Resolution>
<errordetails><errordetail><

code>W5/102</code>
<message>S:W5:102 0010017899</message>

<propertyref/>
<severity>error</severity>
</errordetail><errordetail>

<code>W5/102</code>
<message>S:W5:102 0010017899</message>
<propertyref/>
<severity>error</severity>
</errordetail><errordetail>

<code>/IWBEP/CX_SD_GEN_DPC_BUSINS</code>
<message> --- Order is checked and approved ----</message>
<propertyref/>
<severity>error</severity>
</errordetail></errordetails>
</innererror></error> 

但我只想得到一行 --- 订单已检查并批准 ---- /IWBEP/CX_SD_GEN_DPC_BUSINS。

如何通过 $errormessage = $xml.find( "message"); 上的哪个参数获取它

谢谢..

Answer 1

这是我的版本 - 花了一段时间，所以有人在我玩的时候发布了

显示

--- 订单已检查并批准 ----

    var xml = '<error><code>SY/530</code><message xml:lang="en">S:W5:102 0010017899</message><innererror><transactionid>A831E4E4ADFDF1998E50005056AA3F7A</transactionid><timestamp/><Error_Resolution><SAP_Transaction/><SAP_Note/></Error_Resolution><errordetails><errordetail><code>W5/102</code><message>S:W5:102 0010017899</message><propertyref/><severity>error</severity></errordetail><errordetail><code>W5/102</code><message>S:W5:102 0010017899</message><propertyref/><severity>error</severity></errordetail><errordetail><code>/IWBEP/CX_SD_GEN_DPC_BUSINS</code><message> --- Order is checked and approved ----</message><propertyref/><severity>error</severity></errordetail></errordetails></innererror></error>'
    
    var xmlDoc = $.parseXML(xml),$xml = $(xmlDoc);
    var messages = $xml.find("message");
    var message = messages.filter(function(i,msg) {
        console.log(msg)
         return msg.textContent.indexOf("---") !=-1;
    });
    console.log(message[0].textContent)

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