javascript - 以不同的顺序混洗两个不同的数组

Question

我有两副牌:

var cardDeck = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, "J", "Q", "K", "A"];
var player1Deck = shuffle(cardDeck);
var player2Deck = shuffle(cardDeck);

打乱顺序:

function shuffle(o){
    for(var j, x, i = o.length; i; j = Math.floor(Math.random() * i), x = o[--i], o[i] = o[j], o[j] = x);
    return o;
};

但是，它们都以相同的顺序洗牌:

player1Deck = [1, 2, "A", 5, 4, 8, "J", 9, 6, 10, "Q", 7, 3, "K"];
player2Deck = [1, 2, "A", 5, 4, 8, "J", 9, 6, 10, "Q", 7, 3, "K"];

相反，我希望牌组以不同的方式洗牌，如下所示:

player1Deck = [1, 2, "A", 5, 4, 8, "J", 9, 6, 10, "Q", 7, 3, "K"];
player2Deck = ["A", 3, 1, 8, 4, 5, "K", 7, "Q", 10, 6, 9, 2, "J"];

如果可能的话，我想仅将其保留在 Javascript 中。

Answer 1

问题是您的洗牌方法进行了内联洗牌，因此返回了相同的实例。

因此，将原始数组的副本传递给 shuffle 方法，为此您可以使用 slice(0) 方法

var cardDeck = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, "J", "Q", "K", "A"];
var player1Deck = shuffle(cardDeck.slice(0));
var player2Deck = shuffle(cardDeck.slice(0));