iphone - 使用 AFNetworking 发布请求

Question

我是编程新手，尤其是在网络方面。所以现在我正在创建与 Instagram 交互的应用程序。在我的项目中，我使用 AFNetworking。我在这里看到了他们的文档和许多示例。而且我还不明白如何向 Instagram API 发送 POST 请求。请给我真实的代码示例或我可以阅读有关如何执行此操作的内容？请帮忙。我试图提出这样的请求，它没有给出错误也没有响应。它什么也没给 :(

(IBAction)doRequest:(id)sender{

NSURL *baseURL = [NSURL URLWithString:@"http://api.instagram.com/"];

AFHTTPClient *httpClient = [[AFHTTPClient alloc] initWithBaseURL:baseURL];
[httpClient defaultValueForHeader:@"Accept"];

NSDictionary *params = [NSDictionary dictionaryWithObjectsAndKeys:
                        user_token, @"access_token",
                        nil];

[httpClient postPath:@"/feed" parameters:params success:^(AFHTTPRequestOperation *operation, id responseObject) {
    // reponseObject will hold the data returned by the server.
    NSLog(@"data: %@", responseObject);
}failure:^(AFHTTPRequestOperation *operation, NSError *error) {
    NSLog(@"Error retrieving data: %@", error);
}];


NSLog(@"click!!");
}

Answer 1

需要注意的事情很少。Instagram API 返回 JSON，因此您可以使用 AFJSONRequestOperation，它会返回一个已解析的 NSDictionary。
Instagram API 表示:

All endpoints are only accessible via https and are located at api.instagram.com.

您应该更改您的 baseURL。

AFHTTPClient *client = [AFHTTPClient clientWithBaseURL:yourURL];
NSURLRequest *request = [client requestWithMethod:@"POST"
                                             path:@"/your/path"
                                       parameters:yourParamsDictionary];
AFJSONRequestOperation *operation =
[AFJSONRequestOperation
 JSONRequestOperationWithRequest:request
 success:^(NSURLRequest *request, NSHTTPURLResponse *response, id JSON)
{
    // Do something with JSON
}
 failure:^(NSURLRequest *request, NSHTTPURLResponse *response, NSError *error, id JSON)
{
    // 
}];

// you can either start your operation like this 
[operation start];

// or enqueue it in the client default operations queue.
[client enqueueHTTPRequestOperation:operation];