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python - 抓取 Google Scholar 时防止 503 错误

转载 作者:行者123 更新时间:2023-11-28 19:10:18 31 4
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我编写了以下代码来从 Google Scholar security page. 中抓取数据.但是,每当我运行它时,我都会收到此错误:

 Traceback (most recent call last):
File "/Users/.../Documents/GS_Tag_Scraper/scrape-modified.py", line 53, in <module>
getProfileFromTag(each)
File "/Users/.../Documents/GS_Tag_Scraper/scrape-modified.py", line 32, in getProfileFromTag
page = urllib.request.urlopen(url)
File "/Users/.../anaconda/lib/python3.5/urllib/request.py", line 163, in urlopen
return opener.open(url, data, timeout)
File "/Users/.../anaconda/lib/python3.5/urllib/request.py", line 472, in open
response = meth(req, response)
File "/Users/.../anaconda/lib/python3.5/urllib/request.py", line 582, in http_response
'http', request, response, code, msg, hdrs)
File "/Users/.../anaconda/lib/python3.5/urllib/request.py", line 504, in error
result = self._call_chain(*args)
File "/Users/.../anaconda/lib/python3.5/urllib/request.py", line 444, in _call_chain
result = func(*args)
File "/Users/.../anaconda/lib/python3.5/urllib/request.py", line 696, in http_error_302
return self.parent.open(new, timeout=req.timeout)
File "/Users/.../anaconda/lib/python3.5/urllib/request.py", line 472, in open
response = meth(req, response)
File "/Users/.../anaconda/lib/python3.5/urllib/request.py", line 582, in http_response
'http', request, response, code, msg, hdrs)
File "/Users/.../anaconda/lib/python3.5/urllib/request.py", line 510, in error
return self._call_chain(*args)
File "/Users/.../anaconda/lib/python3.5/urllib/request.py", line 444, in _call_chain
result = func(*args)
File "/Users/.../anaconda/lib/python3.5/urllib/request.py", line 590, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 503: Service Unavailable

我认为这是因为 GS 阻止了我的请求。我怎样才能避免这种情况?

代码是:

# -*- coding: utf-8 -*-
from bs4 import BeautifulSoup
import urllib.request
import string
import csv
import time

#Declares array's to store data
name = []
urlList =[]

#Opens and writer header of CSV file
outputFile = open('sample.csv', 'w', newline='')
outputWriter = csv.writer(outputFile)
outputWriter.writerow(['Name', 'URL', 'Total Citations', 'h-index', 'i10-index'])

def getStat (url):
#Given an authors URL it retunrs an array of stats.
url = 'https://scholar.google.pl' + url
page = urllib.request.urlopen(url)
soup = BeautifulSoup(page, 'lxml')
buttons = soup.findAll("td", { "class" : "gsc_rsb_std" })
list=[]
return (list)

def getProfileFromTag(tag):
url = "http://scholar.google.pl/citations?view_op=search_authors&hl=pl&mauthors=label:" + tag
while True:
page = urllib.request.urlopen(url)
soup = BeautifulSoup(page, 'lxml')

mydivs = BeautifulSoup(urllib.request.urlopen(url), 'lxml').findAll("h3", { "class" : "gsc_1usr_name"})
for each in mydivs:
for anchor in each.find_all('a'):
name.append(anchor.text)
urlList.append(anchor['href'])
time.sleep(0.001)
buttons = soup.findAll("button", {"aria-label": "Następna"})
if not buttons:
break
on_click = buttons[0].get('onclick')
url = 'http://scholar.google.pl' + on_click[17:-1]
url = url.encode('utf-8').decode('unicode_escape')
for each in name:
list = getStat(urlList[i])
outputWriter.writerow([each, urlList[i], list[0], list[2], list[4]])

tags = ['security']
for each in tags:
getProfileFromTag(each)

最佳答案

改为使用 requests 以及适当的请求 header 。

import requests

url = 'https://scholar.google.pl/citations?view_op=search_authors&mauthors=label:security'

request_headers = {
'accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
'accept-encoding': 'gzip, deflate, br',
'accept-language': 'en-US,en;q=0.8',
'upgrade-insecure-requests': '1',
'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/61.0.3163.100 Safari/537.36'
}

with requests.Session() as s:
r = s.get(url, headers=request_headers)

得到的结果:

Adrian Perrig    /citations?user=n-Oret4AAAAJ&hl=pl
Vern Paxson /citations?user=HvwPRJ0AAAAJ&hl=pl
Frans Kaashoek /citations?user=YCoLskoAAAAJ&hl=pl
Mihir Bellare /citations?user=2pW1g5IAAAAJ&hl=pl
Xuemin Shen /citations?user=Bjl3GwoAAAAJ&hl=pl
Helen J. Wang /citations?user=qhu-DxwAAAAJ&hl=pl
Sushil Jajodia /citations?user=lOZ1vHIAAAAJ&hl=pl
Martin Abadi /citations?user=vWTI60AAAAAJ&hl=pl
Jean-Pierre Hubaux /citations?user=W7YBLlEAAAAJ&hl=pl
Ross Anderson /citations?user=WgyDcoUAAAAJ&hl=pl

使用这个:

users = soup.findAll('h3', {'class': 'gsc_oai_name'})
for user in users:
name = user.a.text.strip()
link = user.a['href']
print(name, '\t', link)

您可以通过研究 Chrome 开发者工具的网络选项卡找到浏览器发送的 header 。

关于python - 抓取 Google Scholar 时防止 503 错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41331881/

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