javascript - 展平数组并保留索引作为其位置值

Question

$scope.data = [[1,2,3], [1,5,6,7], [2,3]];

我会用_.flatten($scope.data)所以scope.data会是这样的

$scope.data = [1,2,3,1,5,6,7,2,3];

但我想保留数组的索引在每个被展平的元素中

所以我会有类似的东西:

$scope.data = [{value:1, index:1},
                  {value:2, index:1},
                  {value:3, index:1},
                  {value:1, index:2},
                  {value:5, index:2},
                  {value:6, index:2},
                  {value:7, index:2},
                  {value:2, index:3}
                  {value:3, index:3}];

Answer 1

您可以像这样循环遍历原始数组:

function flatten(arr)
{
    var returnArray = new Array();
    for(var i = 0; i < arr.length; i++)
    {
        for(var j = 0; j < arr[i].length; j++)
        {
            returnArray.push({"value" : arr[i][j], "index" : i});
        }
    }
    return returnArray;
}

输出: