ios - 尝试在其 View 不在窗口层次结构中的 ViewController 上呈现

Question

这是在主菜单上使用的代码，当用户按下播放键时，但是当显示该屏幕时 (ViewController.m) 它会显示错误

警告:尝试呈现不在窗口层次结构中的 View !

-(IBAction)play:(id)sender
{
    if(IS_IPAD)
    {
        ViewController *view_obj = [[ViewController alloc]initWithNibName:@"ViewController_iPad" bundle:[NSBundle mainBundle]];
        [self presentViewController:view_obj animated:YES completion:nil];

    }
    else if ([AISGlobal isIphone5thGeneration])
    {
        ViewController *view_obj = [[ViewController alloc]initWithNibName:@"ViewController_iPhone5" bundle:[NSBundle mainBundle]];
        [self presentViewController:view_obj animated:YES completion:nil];


    }
    else
    {
        ViewController *view_obj = [[ViewController alloc]initWithNibName:@"ViewController_iPhone" bundle:[NSBundle mainBundle]];
        [self presentViewController:view_obj animated:YES completion:nil];

    }

}

在 AppDelegate.m 文件中，它在“didFinishLaunchingWithOptions”部分显示了这一点；

if(IS_IPAD)
    {
         self.start_screen_obj = [[Start_screen alloc] initWithNibName:@"Start_screen" bundle:nil];
    }
    else if ([AISGlobal isIphone5thGeneration])
    {
        self.start_screen_obj = [[Start_screen alloc] initWithNibName:@"Start_screen_iphone5" bundle:nil];

    }
    else
    {
       self.start_screen_obj = [[Start_screen alloc] initWithNibName:@"Start_screen_iphone" bundle:nil];
    }

    self.start_screen_obj.view.multipleTouchEnabled = YES;

    self.window.rootViewController = self.start_screen_obj;

    [self.window makeKeyAndVisible];

Answer 1

尝试在 View Controller 的 viewDidAppear 方法中编写您的代码，因为直到那时您的 View 才刚刚创建，并没有添加到 View 层次结构中。