javascript - 将多个值从js页面传递到php页面

Question

我想要从服务页面到 php 页面的多个值。我想将 'data'、'albimg'、'albvideo' 传递到 php 页面。现在我发现了如图所示的错误。

var deferred = $q.defer();
            data.pagename = "create_album";
            $http.post('js/data/album.php', {action:{"data":data,"albimg":albimg,"albvideo":albvideo}})
                    .success(function (data, status, headers, config)
                    {
                        console.log(status + ' - ' + action);
                        deferred.resolve(action);
                    })
                    .error(function (action, status, headers, config)
                    {
                        deferred.reject(action);
                        console.log('error');
                    });

            return deferred.promise;
php page:
$postdata = file_get_contents("php://input",true);
$request = json_decode($postdata);
$now = date('Y-m-d H:i:s');
echo $sql="INSERT INTO `$prefix.album` (CONTENT_VALUES,CreatedTime)VALUES('$postdata','$now')";

Answer 1

你可以通过使用 param 属性来做到这一点:像这样；

var data = {"data":data,"albimg":albimg,"albvideo":albvideo};

$http({ url: "js/data/album.php",    method: "POST",    params: data    })