javascript - Jquery inArray 在循环中总是返​​回 -1

Question

我在使用 Jquery inArray 时遇到问题。

//Get selected devices
selectedDevices = $('.selectDevices').val();
console.log(selectedDevices);

//If nothing selected, do nothing
if(selectedDevices == null || selectedDevices == ""){}

    //Else remove devices not selected
    else{ 
        //Loop thru table rows with class "enhet"
        $.each( $('td.enhet'), function() {

        thisDevice = $('.enhet').text();

        var found = $.inArray(thisDevice, selectedDevices);

        console.log(found);

        if (found > -1) {
            console.log(thisDevice);
        }
        else {
            console.log('nope');
        }


    })
}

Console.log(selectedDevices) 给出:
[“GulAvformning”，“RosaAvformning”]

Console.log(找到)给出:(每次!!)
-1

Console.log(thisDevice) 给出:
``

Console.log('nope') 给出:
不

即使 thisdevice 存在于 selectedDevices 中，我也会遇到 else 情况。
我错过了什么？

selectedDevices 是一个数组。我通过以下方式检查:console.log(selectedDevices[1]);它给了我其中一台设备。

Answer 1

对元素使用each()方法，然后使用$(this)来标识当前元素:

selectedDevices = $('.selectDevices').val();
console.log(selectedDevices);

//If nothing selected, do nothing
if(selectedDevices == null || selectedDevices == ""){}

//Else remove devices not selected
else{ 
  //Loop thru table rows with class "enhet"
  $('td.enhet').each(  function() {

    thisDevice = $(this).text(); // use $(this) here

    var found = $.inArray(thisDevice, selectedDevices);

    console.log(found);

    if (found > -1) {
      console.log(thisDevice);
    }
    else {
      console.log('nope');
    }


  })
}