python - 如何列出我的用户帐户的所有照片？

Question

我正在尝试编写一个执行以下操作的脚本:

• 从我的 flickr 帐户获取相册(照片集)ID 的列表
• 将每个相册(照片集)中的图像标题列在一个名为相册标题的文本文件中

这是我目前所拥有的:

import flickrapi

from xml.etree import ElementTree

api_key = 'xxxx'
api_secret = 'xxxx'

flickr = flickrapi.FlickrAPI(api_key, api_secret)

(token, frob) = flickr.get_token_part_one(perms='write')
if not token: raw_input("Press ENTER after you authorized this program")
flickr.get_token_part_two((token, frob))

sets = flickr.photosets_getList(user_id='xxxx')

for elm in sets.getchildren()[0]:
    title = elm.getchildren()[0].text
    print ("id: %s setname: %s photos: %s") %(elm.get('id'), title, elm.get('photos'))

上面简单的把结果输出到屏幕上是这样的:

id: 12453463463252553 setname: 2006-08 photos: 371
id: 23523523523532523 setname: 2006-07 photos: 507
id: 53253253253255532 setname: 2006-06 photos: 20
... etc ...

从那里，我得到了以下我认为会列出上述相册中所​​有图像标题的信息:

import flickrapi

from xml.etree import ElementTree

api_key = 'xxxx'
api_secret = 'xxxx'

flickr = flickrapi.FlickrAPI(api_key, api_secret)

(token, frob) = flickr.get_token_part_one(perms='write')
if not token: raw_input("Press ENTER after you authorized this program")
flickr.get_token_part_two((token, frob))

photos = flickr.photosets_getPhotos(photoset_id='12453463463252553')

for elm in photos.getchildren()[0]:
    title = elm.getchildren()[0].text
    print ("%s") %(elm.get('title'))

不幸的是，它只是吐出一个索引超出范围的索引错误。

Answer 1

我坚持了下来，并在 friend 的帮助下提出了以下按计划工作的方法:

import flickrapi
import os
from xml.etree import ElementTree

api_key = 'xxxx'
api_secret = 'xxxx'

flickr = flickrapi.FlickrAPI(api_key, api_secret)

(token, frob) = flickr.get_token_part_one(perms='write')
if not token: raw_input("Press ENTER after you authorized this program")
flickr.get_token_part_two((token, frob))


sets = flickr.photosets_getList(user_id='xxxx')

for set in sets.getchildren()[0]:
    title = set.getchildren()[0].text

    filename = "%s.txt" % (title)
    f = open(filename,'w')

    print ("Getting Photos from set: %s") % (title)

    for photo in flickr.walk_set(set.get('id')):
                f.write("%s" % (photo.get('title')))


    f.close()