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python - 在 simpy python 中请求第一个可用资源

转载 作者:行者123 更新时间:2023-11-28 18:42:05 41 4
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我想创建一个仿真模型来模拟具有 3 个柜台的银行。我希望有一个客户队列,如果有任何一个柜台可用,它将为该柜台服务一段时间。每个柜台都是自己的简单资源(我不能做一个容量为 3 的资源),我需要知道哪个柜台为客户服务。我在实现时遇到了问题。

我找到了这篇文章,似乎是关于同样的问题,但仍然不知 Prop 体的实现http://comments.gmane.org/gmane.comp.python.simpy.user/1754

我假设我需要一个 yield simpy.AnyOf(env, list_of_resources) 来请求第一个可用的计数器,但我不知道如何正确设置它,以及如果多个资源同时可用时间,我想要一些方法来检查这个,以便我可以选择哪个柜台更适合客户去。

我正在运行 python 版本 2.7,simpy 版本 3.0.4

编辑添加代码,显示我正在尝试做什么以及它现在如何不起作用。

import simpy
import random

LENGTH_SIM = 200.0

class Customer(object):
def __init__(self, arrive_time, num):
self.arrive_time = arrive_time
self.start_service_time = -1.0
self.finish_service_time = -1.0
self.served_by = -1.0
self.num = num
def print_attributes(self):
format_string = "#%3d Arrive: %6.1f Start Service: %6.1f "\
+ " End Service: %6.1f" + " Served By: %3d"
print format_string %(self.num, self.arrive_time,
self.start_service_time,
self.finish_service_time, self.served_by)

class Counter(object):
def __init__(self, number):
self.number = number
self.name = "Counter " + str(number)
self.start_times = []
self.end_times = []

class Bank(object):
def __init__(self, env, num_counters):
self.counters = [Counter(x+1) for x in range(num_counters)]
self.num_counters = num_counters
self.counters_resources = [simpy.Resource(env, capacity=1)
for x in range(num_counters)]


def generate_customers(env, customers):
count = 1
while 1:
wait_time = random.randint(8, 12)
yield env.timeout(wait_time)
customers.append(Customer(env.now, count))
print "Generated Customer: ", count
count += 1

def select_counter(env, bank):
'''choose a counter for the customer'''
for x in range(len(bank.counters)):
if bank.counters_resources[len(bank.counters) - 1 - x].count == 0:
print "Counter Selected: ", len(bank.counters) - 1 - x
print bank.counters[len(bank.counters) - 1 - x].number
print bank.counters_resources[len(bank.counters) - 1 - x].users
return len(bank.counters) - 1 - x
return -2.0

def gen_service_time():
return random.random() * 20.0 + 21.0

def handle_customer(env, bank, customer, customers, num_process):
'''handles customer'''
print "Process ", num_process, " started at:", env.now
counter = select_counter(env, bank)
print "Process ", num_process, " after counter select:", env.now
if counter != -2.0:
with bank.counters_resources[counter].request() as req:
yield req
print "Process ", num_process, "Time", env.now, "In if"
bank.counters[counter].start_times.append(env.now)
service_time = gen_service_time()
customer.start_service_time = env.now
customer.finish_service_time = env.now + service_time
bank.counters[counter].end_times.append(env.now + service_time)
customer.served_by = counter + 1
yield env.timeout(service_time)
else:
reqs = []
for x in range(len(bank.counters)):
reqs.append(bank.counters_resources[x].request())
counter_used = yield simpy.events.AnyOf(env, reqs)
for x in range(len(reqs)):
if counter_used.keys()[0] != reqs[x]:
print "True"
bank.counters_resources[x].release(reqs[x])
print "Process ", num_process, "Time", env.now, "In else"
bank.counters[0].start_times.append(env.now)
service_time = gen_service_time()
customer.start_service_time = env.now
customer.finish_service_time = env.now + service_time
bank.counters[0].end_times.append(env.now + service_time)
customer.served_by = 1
yield env.timeout(service_time)
for x in range(len(reqs)):
## if counter_used.keys()[0] == reqs[x]:
if 1:
bank.counters_resources[x].release(reqs[x])




def run_bank(env, bank, customers):
while 1:
min_time = -1.0
min_customer = -1.0
for x in xrange(len(customers)):
if customers[x].arrive_time < min_time or min_time == -1.0:
if customers[x].arrive_time > env.now:
min_time = customers[x].arrive_time
min_customer = x
else:
continue
if min_time == -1.0:
yield env.timeout(LENGTH_SIM - env.now)
yield env.timeout(min_time - env.now)
print "Calling Process: ", min_customer, "At time:", env.now
env.process(handle_customer(env,bank,customers[min_customer],customers,
min_customer + 1))

def run_sim():
env = simpy.Environment()
customers = []
env.process(generate_customers(env, customers))
env.run(until=LENGTH_SIM)
env2 = simpy.Environment()
bank = Bank(env2, 3)
env2.process(run_bank(env2, bank, customers))
env2.run(until = LENGTH_SIM)
for x in range(len(customers)):
customers[x].print_attributes()

if __name__ == '__main__':
run_sim()

最佳答案

如果你真的不能使用容量为 3 的普通 Resource,也许 Store 可以帮助你。 Store 存储您可以请求的计数器对象。每个计数器都有自己的身份,例如,可以跟踪其使用次数。客户完成后,必须将柜台放回商店:

import simpy


class Counter:
usages = 0


def customer(env, counters):
counter = yield counters.get()
yield env.timeout(1)
counter.usages += 1
yield counters.put(counter)


env = simpy.Environment()
counters = simpy.Store(env, capacity=3)
counters.items = [Counter() for i in range(counters.capacity)]
for i in range(10):
env.process(customer(env, counters))
env.run()
for counter in counters.items:
print(counter.usages)

关于python - 在 simpy python 中请求第一个可用资源,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25046946/

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