iOS 将 IP 地址转换为整数并向后转换

Question

假设我有一个 NSStringNSString *myIpAddress = @"192.168.1.1"

我想将其转换为整数 - 递增它然后将其转换回 NSString。

除了使用位掩码、移位和 sprintf 之外，iOS 有没有简单的方法来做到这一点？

Answer 1

我在 my app 中就是这样做的:

NSArray *ipExplode = [string componentsSeparatedByString:@"."];
int seg1 = [ipExplode[0] intValue];
int seg2 = [ipExplode[1] intValue];
int seg3 = [ipExplode[2] intValue];
int seg4 = [ipExplode[3] intValue];

uint32_t newIP = 0;
newIP |= (uint32_t)((seg1 & 0xFF) << 24);
newIP |= (uint32_t)((seg2 & 0xFF) << 16);
newIP |= (uint32_t)((seg3 & 0xFF) << 8);
newIP |= (uint32_t)((seg4 & 0xFF) << 0);

newIP++;
NSString *newIPStr = [NSString stringWithFormat:@"%u.%u.%u.%u", 
        ((newIP >> 24) & 0xFF), 
        ((newIP >> 16) & 0xFF), 
        ((newIP >> 8) & 0xFF), 
        ((newIP >> 0) & 0xFF)];