javascript - 如何用javascript捕获url字符串的一部分

Question

我有一个像这样的网址字符串:example.com/sfm?dir=uploads/sfm/root/folder1/subfolder1

是否可以用javascript只捕获=后面的部分？所以捕获的部分应该是这样的:uploads/sfm/root/folder1/subfolder1

Answer 1

您可以尝试这个(取自MDN):

var getQueryVarByName = function (name)
{
    name = name.replace(/[\[]/, "\\[").replace(/[\]]/, "\\]");
    var regex = new RegExp("[\\?&]" + name + "=([^&#]*)"),
        results = regex.exec(location.search);
    return results === null ? "" : decodeURIComponent(results[1].replace(/\+/g, " "));
};

用途:

var param = getQueryVarByName('dir'); // uploads/sfm/root/folder1/subfolder1