python - 使用 lxml 和请求进行 Web 抓取

Question

我有一个 web page对于酒店，我想获取所有酒店名称。我按照 this page 的说明编写了代码，但没有成功。我的代码在这里:

from lxml import html
import requests

page = requests.get('web page url')
tree = html.fromstring(page.content)

hotel_name = tree.xpath('//span[@title="sr-hotel__name"]/text()')

print(hotel_name)

我得到的只是一个空列表。有帮助吗？

Answer 1

您需要添加一个用户代理:

from lxml import html
import requests
headers= {"User-Agent":"Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/52.0.2743.82 Safari/537.36"}
page = requests.get('http://www.booking.com/searchresults.et.html?label=gen173nr-1FCAEoggJCAlhYSDNiBW5vcmVmaEKIAQGYAQu4AQbIAQzYAQHoAQH4AQuoAgM&sid=1bc09296ee139ec3cb0edce87d7fb20a&dcid=1&class_interval=1&dest_id=67&dest_type=country&dtdisc=0&group_adults=2&group_children=0&hlrd=0&hyb_red=0&inac=0&label_click=undef&nha_red=0&no_rooms=1&postcard=0&redirected_from_city=0&redirected_from_landmark=0&redirected_from_region=0&review_score_group=empty&room1=A%2CA&sb_price_type=total&score_min=0&src=index&ss=Eesti&ss_all=0&ss_raw=Eesti&ssb=empty&sshis=0&traveller=other&nflt=ht_id%3D204%3B&lsf=ht_id%7C204%7C221&unchecked_filter=hoteltype'
                    , headers=headers)
tree = html.fromstring(page.content)
print(page.text)
hotel_name = tree.xpath('//span[@class="sr-hotel__name"]/text()')

print(hotel_name)

这会给你:

['\nHotel Telegraaf\n', '\nRadisson Blu Hotel Olümpia\n', '\nRadisson Blu Sky Hotel\n', '\nPark Inn by Radisson Central Tallinn\n', '\nPark Inn by Radisson Meriton Conference & Spa Hotel Tallinn\n', '\nMerchants House Hotel\n', '\nSwissotel Tallinn\n', '\nMy City Hotel\n', '\nNordic Hotel Forum\n', '\nHotel Palace by TallinnHotels\n', '\nHotel Ülemiste\n', '\nTallink City Hotel\n', '\nHotel London by Tartuhotels\n', '\nJohan Design & SPA Hotel\n', '\nThe von Stackelberg Hotel Tallinn\n']

但是你应该阅读他们的 TOS :

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