Python Not - 将参数传递给命令处理程序

Question

我正在玩 Python Telegram Bot，我想将通过先前计算获得的参数传递给我的处理程序，例如:

def my_handler(bot, update, param):
    print(param)

def main():
    res = some_function()
    updater.dispatcher.add_handler(CommandHandler('cmd', my_handler))

如何将参数传递给处理程序？

Answer 1

在版本 12 的 python-telegram-bot 中，参数作为列表位于属性 CallbackContext.args 中。这是一个通用示例:

def my_handler(update, context):
    print(context.args)

def main():
    res = some_function()
    updater.dispatcher.add_handler(CommandHandler('cmd', my_handler))

一个简单的例子是将两个整数相加:

import logging
from config import tgtoken
from telegram.ext import Updater, CommandHandler

logging.basicConfig(format='%(asctime)s - %(name)s - %(levelname)s - %(message)s',
                    level=logging.INFO)

logger = logging.getLogger(__name__)

def error(update, context):
    """Log Errors caused by Updates."""
    logger.warning('Update "%s" caused error "%s"', update, context.error)

def sum(update, context):
    try:
        number1 = int(context.args[0])
        number2 = int(context.args[1])
        result = number1+number2
        update.message.reply_text('The sum is: '+str(result))
    except (IndexError, ValueError):
        update.message.reply_text('There are not enough numbers')

def main():
    updater = Updater(tgtoken, use_context=True)
    dp = updater.dispatcher
    dp.add_handler(CommandHandler("sum", sum))
    dp.add_error_handler(error)
    updater.start_polling()
    updater.idle()

if __name__ == '__main__':
    main()

如果您发送/sum 1 2，您的机器人将回答The sum is: 3