javascript - Nn 算法将单个数字除三倍 Javascript

Question

我正在尝试创建一种将单个数字除三的算法。我已经创建了这段代码，但由于某种原因它不起作用，我不知道为什么。

有人可以让我深入了解我做错了什么吗？

HTML

<form id="frm1">
  Budget: <input id="budget" type="text" name="budget" value="110"><br>
  <br>

  Domestic: 
  <input id="low" type="text" name="low" value="20">%<br>
  <input id="lowresult" type="text" name="low" oninput="calculate()"><br>

  Continental:
  <input id="med" type="text" name="med" value="30">% <br>
  <input id="medresult" type="text" name="med" oninput="calculate()"><br>

  International:
  <input id="high" type="text" name="high" value="50">% <br>
  <input id="highresult" type="text" name="high" oninput="calculate()"><br>
  <br>

</form>

Javascript

function calculate() {

var budget = document.getElementById("budget").value;
var low = document.getElementById('low').value;
var med = document.getElementById('med').value;
var high = document.getElementById('high').value;

var lowResult = document.getElementById('lowresult');
var medResult = document.getElementById('medresult');
var highResult = document.getElementById('highresult');

var lowFinalResult = (budget /100)*low;
    lowResult.value = lowResult;

var medFinalResult = (budget /100)*med;
    medResult.value = medResult;

var highFinalResult = (budget /100)*high;
    highResult.value = highResult;


}

Answer 1

调整javascript

这个

var lowFinalResult = (budget /100)*low;
    lowResult.value = lowFinalResult;

而不是

var lowFinalResult = (budget /100)*low;
    lowResult.value = lowResult;

完整代码

function calculate() {

var budget = document.getElementById("budget").value;
var low = document.getElementById('low').value;
var med = document.getElementById('med').value;
var high = document.getElementById('high').value;

var lowResult = document.getElementById('lowresult');
var medResult = document.getElementById('medresult');
var highResult = document.getElementById('highresult');

var lowFinalResult = (budget /100)*low;
    lowResult.value = lowFinalResult;

var medFinalResult = (budget /100)*med;
    medResult.value = medFinalResult;

var highFinalResult = (budget /100)*high;
    highResult.value = highFinalResult;


}