ios - Swift - 提取值(value)的正则表达式

Question

我想从具有唯一开始和结束字符的字符串中提取值。就我而言，它是 em

"Fully <em>Furni<\/em>shed |Downtown and Canal Views",

结果

Furnished

Answer 1

我猜你想删除标签。

如果反斜杠只是虚拟的，则模式非常简单:基本上是 <em>带可选斜杠 /?

let trimmedString = string.replacingOccurrences(of: "</?em>", with: "", options: .regularExpression)

还要考虑它的反斜杠

let trimmedString = string.replacingOccurrences(of: "<\\\\?/?em>", with: "", options: .regularExpression)

---

如果你只想提取 Furnished 您必须捕获组:标记之间的字符串以及结束标记之后的所有内容，直到下一个空白字符。

let string = "Fully <em>Furni<\\/em>shed |Downtown and Canal Views"
let pattern = "<em>(.*)<\\\\?/em>(\\S+)"
do {
    let regex = try NSRegularExpression(pattern: pattern)
    if let match = regex.firstMatch(in: string, range: NSRange(string.startIndex..., in: string)) {
        let part1 = string[Range(match.range(at: 1), in: string)!]
        let part2 = string[Range(match.range(at: 2), in: string)!]
        print(String(part1 + part2))
    }
} catch { print(error) }